OCR MEI Further Extra Pure 2019 June — Question 3 8 marks

Exam BoardOCR MEI
ModuleFurther Extra Pure (Further Extra Pure)
Year2019
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
Topic3x3 Matrices
TypeCayley-Hamilton and characteristic equation
DifficultyChallenging +1.2 This is a Further Maths question requiring knowledge of the Cayley-Hamilton theorem and matrix inversion through it. While the theorem itself is advanced, the application is mechanical: find the characteristic polynomial, substitute A, rearrange to isolate A^{-1}. The 3×3 matrix requires careful arithmetic but follows a standard procedure with no novel insight needed. Slightly above average difficulty due to the Further Maths content and computational demands.
Spec4.03o Inverse 3x3 matrix

The matrix A is \(\begin{pmatrix} -1 & 2 & 4 \\ 0 & -1 & -25 \\ -3 & 5 & -1 \end{pmatrix}\). Use the Cayley-Hamilton theorem to find A\(^{-1}\). [8]

Question 3:
AnswerMarks
3-1-l 2 4
0 -1-l -25
-3 5 -1-l
( ) ( )
=(-1-l) (-1-l)2+125 -2(-75)+4 3(-1-l)
=-1-3l-3l2-l3-125-125l+150-12-12l
=-l3-3l2-140l+12
-A3-3A2-140A+12I=O
A -1= 1 (A2+3A+140I)oe
12
æ ö
-11 16 -58
ç ÷
A2 = 75 -124 50 and
ç ÷
ç 6 -16 -136 ÷
è ø
æ ö
-3 6 12
ç ÷
3A= 0 -3 -75 [+140I]
ç ÷
ç -9 15 -3 ÷
è ø
æ ö
126 22 -46
1 ç ÷
A -1= 75 13 -25 oe
ç ÷
12
ç -3 -1 1 ÷
AnswerMarks
è øM1
M1
A1
B1
M1
A1ft
B1
A1
cao
AnswerMarks
[8]1.1a
1.1
1.1
1.1a
1.1a
1.1
1.1
AnswerMarks
1.1Formation of appropriate
determinant
oe, e.g. expansion by first column
Characteristic polynomial
correctly simplified
C-H theorem; condone missing I
and/or 0 for O but must be their
characteristic equation
Using the equation to find the
inverse
Must include I
for A2
BC
AnswerMarks
BC(May be implied)
Allow one minor slip
soi
soi
AnswerMarks Guidance
34 3
Question 3:
3 | -1-l 2 4
0 -1-l -25
-3 5 -1-l
( ) ( )
=(-1-l) (-1-l)2+125 -2(-75)+4 3(-1-l)
=-1-3l-3l2-l3-125-125l+150-12-12l
=-l3-3l2-140l+12
-A3-3A2-140A+12I=O
A -1= 1 (A2+3A+140I)oe
12
æ ö
-11 16 -58
ç ÷
A2 = 75 -124 50 and
ç ÷
ç 6 -16 -136 ÷
è ø
æ ö
-3 6 12
ç ÷
3A= 0 -3 -75 [+140I]
ç ÷
ç -9 15 -3 ÷
è ø
æ ö
126 22 -46
1 ç ÷
A -1= 75 13 -25 oe
ç ÷
12
ç -3 -1 1 ÷
è ø | M1
M1
A1
B1
M1
A1ft
B1
A1
cao
[8] | 1.1a
1.1
1.1
1.1a
1.1a
1.1
1.1
1.1 | Formation of appropriate
determinant
oe, e.g. expansion by first column
Characteristic polynomial
correctly simplified
C-H theorem; condone missing I
and/or 0 for O but must be their
characteristic equation
Using the equation to find the
inverse
Must include I
for A2
BC
BC | (May be implied)
Allow one minor slip
soi
soi
3 | 4 | 3 | 2 | 1
The matrix A is $\begin{pmatrix} -1 & 2 & 4 \\ 0 & -1 & -25 \\ -3 & 5 & -1 \end{pmatrix}$.

Use the Cayley-Hamilton theorem to find A$^{-1}$. [8]

\hfill \mbox{\textit{OCR MEI Further Extra Pure 2019 Q3 [8]}}