OCR MEI Further Pure Core Specimen — Question 14 18 marks

Exam BoardOCR MEI
ModuleFurther Pure Core (Further Pure Core)
SessionSpecimen
Marks18
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex numbers 2
TypeDe Moivre to derive trigonometric identities
DifficultyChallenging +1.2 This is a standard Further Maths question on De Moivre's theorem and complex exponentials. Parts (i) are bookwork proofs requiring straightforward manipulation. Parts (ii) and (iii) involve binomial expansion and algebraic manipulation to find coefficients, which is methodical but lengthy. Part (iv) requires substituting a specific angle and simplifying, which is computational rather than conceptually demanding. While this covers multiple techniques and requires careful algebra, it follows well-established patterns for this topic with no novel insights needed.
Spec4.02n Euler's formula: e^(i*theta) = cos(theta) + i*sin(theta)4.02q De Moivre's theorem: multiple angle formulae

  1. Starting with the result $$e^{i\theta} = \cos \theta + i \sin \theta,$$ show that
    1. \((\cos \theta + i \sin \theta)^n = \cos n\theta + i \sin n\theta\) [2]
    2. \(\cos \theta = \frac{1}{2}(e^{i\theta} + e^{-i\theta})\). [2]
  2. Using the result in part (i) (A), obtain the values of the constants \(a\), \(b\), \(c\) and \(d\) in the identity $$\cos 6\theta = a \cos^6 \theta + b \cos^4 \theta + c \cos^2 \theta + d.$$ [6]
  3. Using the result in part (i) (B), obtain the values of the constants \(P\), \(Q\), \(R\) and \(S\) in the identity $$\cos^6 \theta = P \cos 6\theta + Q \cos 4\theta + R \cos 2\theta + S.$$ [5]
  4. Show that \(\cos \frac{\pi}{12} = \left(\frac{26 + 15\sqrt{3}}{64}\right)^{\frac{1}{4}}\). [3]

Question 14:
AnswerMarks Guidance
14(i) (A)
(cid:32)ein(cid:84)(cid:32)cosn(cid:84)(cid:14)isinn(cid:84) AGM1
A1
AnswerMarks
[2]1.1
2.1n
e
Answer given so working
must be convincing
AnswerMarks Guidance
14(i) (B)
Hence obtain given resultM1
A1
AnswerMarks
[2]m
1.1
AnswerMarks
i2.1Answer given so working
must be convincing
AnswerMarks Guidance
14(ii) e
(cid:11) is(cid:12)6(cid:12)
cos6(cid:84)(cid:32) Re (cid:11)c (cid:14)
p
(cid:32) c6 –15 c4s2 (cid:14)15 c2s4 –s6
(cid:32) c6 –15 c4(cid:11) 1–c2(cid:12) (cid:14)15 c2(cid:11) 1S–c2(cid:12)2 – (cid:11) 1–c2(cid:12)3
AnswerMarks
(cid:32) 32c6 – 48c4 (cid:14) 18c2 – 1c
M1
A1
M1A1
A1A1
AnswerMarks
[6]3.1a
2.1
2.11.1
AnswerMarks
2.2a 1.1A1 any two terms correct, A2
all four
a, b, c, d implicit or explicit
AnswerMarks Guidance
14(iii) 6 6
(cid:167)1(cid:183) (cid:167) 1(cid:183)
cos6(cid:84)(cid:32)(cid:168) (cid:184) (cid:168)z(cid:14) (cid:184) where z(cid:32)ei(cid:84)
(cid:169)2(cid:185) (cid:169) z(cid:185)
1 (cid:167) 1 (cid:167) 1 (cid:183) (cid:167) 1 (cid:183) (cid:183)
(cid:32) (cid:168)z6 (cid:14) (cid:14)6 z4 (cid:14) (cid:14)15 z2 (cid:14) (cid:14)20(cid:184)
(cid:168) (cid:184) (cid:168) (cid:184)
64(cid:169) z6 (cid:169) z4 (cid:185) (cid:169) z2 (cid:185) (cid:185)
1 6 15 5
(cid:32) cos6(cid:84)(cid:14) cos4(cid:84)(cid:14) cos2(cid:84)(cid:14)
AnswerMarks
32 32 32 16M1
A1
M1
A2
AnswerMarks
[5]3.1a
2.1
1.1
AnswerMarks
2.2a 1.1set up expansion
result of expansion
collecting terms
n
A1 for any two coefficients
ecorrect,
A2 all four P, Q, R, S
implicit or explicit
AnswerMarks Guidance
14(iv) Use result in part (iii):
(cid:83) 1 (cid:83) 6 (cid:83) 15 (cid:83) 5
cos6 (cid:32) cos (cid:14) cos (cid:14) cos (cid:14)
12 32 2 32 3 32 6 16
e
1 6 1 15 3 5
(cid:32) (cid:117)0(cid:14) (cid:117) (cid:14) (cid:14) p
32 32 2 32 2 16
S
1
(cid:83) (cid:167)26(cid:14)15 3(cid:183)6
cos (cid:32)(cid:168) (cid:184) AG
(cid:168) (cid:184)
12 64
AnswerMarks
(cid:169) (cid:185)M1
c
A1
A1
AnswerMarks
[3]m
3.1a
i
1.1
AnswerMarks
2.1Putting correct trig values
into their (iii)
Question 14:
14 | (i) | (A) | (cid:11)cos(cid:84)(cid:14) i sin(cid:84)(cid:12)n (cid:32) (cid:11) ei(cid:84)(cid:12)n
(cid:32)ein(cid:84)(cid:32)cosn(cid:84)(cid:14)isinn(cid:84) AG | M1
A1
[2] | 1.1
2.1 | n
e
Answer given so working
must be convincing
14 | (i) | (B) | e(cid:16)i(cid:84) (cid:32) cos(cid:84)– isin(cid:84) AG
Hence obtain given result | M1
A1
[2] | m
1.1
i2.1 | Answer given so working
must be convincing
14 | (ii) | e
(cid:11) is(cid:12)6(cid:12)
cos6(cid:84)(cid:32) Re (cid:11)c (cid:14)
p
(cid:32) c6 –15 c4s2 (cid:14)15 c2s4 –s6
(cid:32) c6 –15 c4(cid:11) 1–c2(cid:12) (cid:14)15 c2(cid:11) 1S–c2(cid:12)2 – (cid:11) 1–c2(cid:12)3
(cid:32) 32c6 – 48c4 (cid:14) 18c2 – 1 | c
M1
A1
M1A1
A1A1
[6] | 3.1a
2.1
2.11.1
2.2a 1.1 | A1 any two terms correct, A2
all four
a, b, c, d implicit or explicit
14 | (iii) | 6 6
(cid:167)1(cid:183) (cid:167) 1(cid:183)
cos6(cid:84)(cid:32)(cid:168) (cid:184) (cid:168)z(cid:14) (cid:184) where z(cid:32)ei(cid:84)
(cid:169)2(cid:185) (cid:169) z(cid:185)
1 (cid:167) 1 (cid:167) 1 (cid:183) (cid:167) 1 (cid:183) (cid:183)
(cid:32) (cid:168)z6 (cid:14) (cid:14)6 z4 (cid:14) (cid:14)15 z2 (cid:14) (cid:14)20(cid:184)
(cid:168) (cid:184) (cid:168) (cid:184)
64(cid:169) z6 (cid:169) z4 (cid:185) (cid:169) z2 (cid:185) (cid:185)
1 6 15 5
(cid:32) cos6(cid:84)(cid:14) cos4(cid:84)(cid:14) cos2(cid:84)(cid:14)
32 32 32 16 | M1
A1
M1
A2
[5] | 3.1a
2.1
1.1
2.2a 1.1 | set up expansion
result of expansion
collecting terms
n
A1 for any two coefficients
ecorrect,
A2 all four P, Q, R, S
implicit or explicit
14 | (iv) | Use result in part (iii):
(cid:83) 1 (cid:83) 6 (cid:83) 15 (cid:83) 5
cos6 (cid:32) cos (cid:14) cos (cid:14) cos (cid:14)
12 32 2 32 3 32 6 16
e
1 6 1 15 3 5
(cid:32) (cid:117)0(cid:14) (cid:117) (cid:14) (cid:14) p
32 32 2 32 2 16
S
1
(cid:83) (cid:167)26(cid:14)15 3(cid:183)6
cos (cid:32)(cid:168) (cid:184) AG
(cid:168) (cid:184)
12 64
(cid:169) (cid:185) | M1
c
A1
A1
[3] | m
3.1a
i
1.1
2.1 | Putting correct trig values
into their (iii)
\begin{enumerate}[label=(\roman*)]
\item Starting with the result
$$e^{i\theta} = \cos \theta + i \sin \theta,$$
show that

\begin{enumerate}[label=(\Alph*)]
\item $(\cos \theta + i \sin \theta)^n = \cos n\theta + i \sin n\theta$ [2]

\item $\cos \theta = \frac{1}{2}(e^{i\theta} + e^{-i\theta})$. [2]
\end{enumerate}

\item Using the result in part (i) (A), obtain the values of the constants $a$, $b$, $c$ and $d$ in the identity
$$\cos 6\theta = a \cos^6 \theta + b \cos^4 \theta + c \cos^2 \theta + d.$$ [6]

\item Using the result in part (i) (B), obtain the values of the constants $P$, $Q$, $R$ and $S$ in the identity
$$\cos^6 \theta = P \cos 6\theta + Q \cos 4\theta + R \cos 2\theta + S.$$ [5]

\item Show that $\cos \frac{\pi}{12} = \left(\frac{26 + 15\sqrt{3}}{64}\right)^{\frac{1}{4}}$. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Pure Core  Q14 [18]}}