OCR MEI Further Pure Core AS Specimen — Question 1 4 marks

Exam BoardOCR MEI
ModuleFurther Pure Core AS (Further Pure Core AS)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeDivision plus modulus/argument
DifficultyModerate -0.8 This is a straightforward Further Maths AS question testing basic complex number conversions and division. Part (i) is direct application of r(cos θ + i sin θ) with standard angle values, and part (ii) requires multiplying by the conjugate—both routine procedures with no problem-solving insight needed. While Further Maths content, the mechanical nature and low mark allocation place it below average difficulty.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02b Express complex numbers: cartesian and modulus-argument forms4.02e Arithmetic of complex numbers: add, subtract, multiply, divide4.02f Convert between forms: cartesian and modulus-argument

The complex number \(z_1\) is \(1+ i\) and the complex number \(z_2\) has modulus 4 and argument \(\frac{\pi}{3}\).
  1. Express \(z_2\) in the form \(a + bi\), giving \(a\) and \(b\) in exact form. [2]
  2. Express \(\frac{z_2}{z_1}\) in the form \(c + di\), giving \(c\) and \(d\) in exact form. [2]

Question 1:
AnswerMarks Guidance
1(i) (cid:167) (cid:83) (cid:83)(cid:183)
z (cid:32)4(cid:168)cos (cid:14)isin (cid:184)
2 (cid:169) 3 3(cid:185)
AnswerMarks
= 2(cid:14)2 3iM1
A1
AnswerMarks Guidance
[2]1.1
1.1May be implied
or exact equivalenta = 2, b = 2 3
1(ii) (cid:11) (cid:12)
2(cid:14)2 3i (cid:11)1(cid:16)i(cid:12)
z
2 (cid:32)
z (cid:11)1(cid:14)i(cid:12)(cid:11)1(cid:16)i(cid:12)
1
(cid:11) (cid:12) (cid:11) (cid:12)
2(cid:14)2 3 (cid:14) 2 3(cid:16)2 i
(cid:32)
2
(cid:11) (cid:12) (cid:11) (cid:12)
AnswerMarks
(cid:32) 3(cid:14)1 (cid:14) 3(cid:16)1 iM1
A1 FT
AnswerMarks
[2]1.1a
M
AnswerMarks
1.1N
FT their z
E2
Must be simplified
Question 1:
1 | (i) | (cid:167) (cid:83) (cid:83)(cid:183)
z (cid:32)4(cid:168)cos (cid:14)isin (cid:184)
2 (cid:169) 3 3(cid:185)
= 2(cid:14)2 3i | M1
A1
[2] | 1.1
1.1 | May be implied
or exact equivalent | a = 2, b = 2 3
1 | (ii) | (cid:11) (cid:12)
2(cid:14)2 3i (cid:11)1(cid:16)i(cid:12)
z
2 (cid:32)
z (cid:11)1(cid:14)i(cid:12)(cid:11)1(cid:16)i(cid:12)
1
(cid:11) (cid:12) (cid:11) (cid:12)
2(cid:14)2 3 (cid:14) 2 3(cid:16)2 i
(cid:32)
2
(cid:11) (cid:12) (cid:11) (cid:12)
(cid:32) 3(cid:14)1 (cid:14) 3(cid:16)1 i | M1
A1 FT
[2] | 1.1a
M
1.1 | N
FT their z
E2
Must be simplified
The complex number $z_1$ is $1+ i$ and the complex number $z_2$ has modulus 4 and argument $\frac{\pi}{3}$.

\begin{enumerate}[label=(\roman*)]
\item Express $z_2$ in the form $a + bi$, giving $a$ and $b$ in exact form. [2]

\item Express $\frac{z_2}{z_1}$ in the form $c + di$, giving $c$ and $d$ in exact form. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Further Pure Core AS  Q1 [4]}}