| Exam Board | CAIE |
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| Module | Further Paper 2 (Further Paper 2) |
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| Year | 2023 |
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| Session | November |
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| Topic | Simultaneous equations |
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1 Show that the system of equations
$$\begin{aligned}
14 x - 4 y + 6 z & = 5
x + y + k z & = 3
- 21 x + 6 y - 9 z & = 14
\end{aligned}$$
where \(k\) is a constant, does not have a unique solution and interpret this situation geometrically.