Standard +0.3 This is a straightforward application of De Moivre's theorem requiring students to convert the RHS to polar form, apply the theorem, and solve for θ. While it's a Further Maths topic, the method is standard and mechanical with no conceptual challenges beyond recognizing the approach.
Find the smallest value \(\theta\) of for which
\((\cos \theta + i \sin \theta)^5 = \frac{1}{\sqrt{2}}(1 - i)\) \(\{\theta \in \mathbb{R} : \theta > 0\}\)
[4 marks]
Question 5:
5 | Uses de Moivre’s theorem | AO3.1a | M1 | 1
cosisin5 1i
2
1
cos5isin5 1i
2
1 1
cos5 sin5
2 2
7π
5
4
7π
20
Equates real and imaginary parts
and obtains two equations | AO1.1a | A1
Deduces that the smallest possible
7π
value of 5 is
4
FT from ‘their’ equations provided
M1 has been awarded | AO2.2a | A1F
Obtains the smallest possible value
of (cid:2016) from fully correct reasoning
FT from ‘their’ 5θ provided M1 has
been awarded | AO1.1b | A1F
Total | 4
Q | Marking Instructions | AO | Marks | Typical Solution
Find the smallest value $\theta$ of for which
$(\cos \theta + i \sin \theta)^5 = \frac{1}{\sqrt{2}}(1 - i)$ $\{\theta \in \mathbb{R} : \theta > 0\}$
[4 marks]
\hfill \mbox{\textit{AQA Further Paper 2 Q5 [4]}}