AQA Further AS Paper 1 2018 June — Question 19 8 marks

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Cross Product & Distances
TypeShortest distance between two skew lines
DifficultyChallenging +1.2 This is a standard 3D vectors question requiring the shortest distance between two skew lines formula. While it involves multiple steps (finding direction vectors, a connecting vector, cross product, and applying the formula), it's a direct application of a well-known technique taught in Further Maths. The 7 marks reflect computational length rather than conceptual difficulty. Part (b) is trivial. Slightly above average due to being Further Maths content and requiring careful calculation.
Spec4.04i Shortest distance: between a point and a line

A theme park has two zip wires. Sarah models the two zip wires as straight lines using coordinates in metres. The ends of one wire are located at \((0, 0, 0)\) and \((0, 100, -20)\) The ends of the other wire are located at \((10, 0, 20)\) and \((-10, 100, -5)\)
  1. Use Sarah's model to find the shortest distance between the zip wires. [7 marks]
  2. State one way in which Sarah's model could be refined. [1 mark]

Question 19:

AnswerMarks Guidance
19(a)Finds a direction vector for the second wire.
Condone one error.3.4 M1
10 −10
�0 �−�100�
20 −5
and
0 0 10 20
𝒓𝒓𝟏𝟏 = �0�+𝜆𝜆�100� 𝒓𝒓𝟐𝟐 = �0 �+𝜇𝜇�−100�
0 −20 20 25
10+20𝜇𝜇
𝒓𝒓𝟐𝟐−𝒓𝒓𝟏𝟏 = �−100𝜇𝜇−100𝜆𝜆�
20+25𝜇𝜇+20𝜆𝜆
and
10+20𝜇𝜇 0 10+20𝜇𝜇 20
�−100𝜇𝜇−100𝜆𝜆�.�100�= 0 �−100𝜇𝜇−100𝜆𝜆�.�−100�= 0
20+25𝜇𝜇+20𝜆𝜆 −20 20+25𝜇𝜇+20𝜆𝜆 and2 5
−10000𝜇𝜇−10000𝜆𝜆−400 −500𝜇𝜇−400𝜆𝜆 = 0
200+400𝜇𝜇+10000𝜇𝜇+1 0 0a0n0d𝜆𝜆 +500+625𝜇𝜇+500𝜆𝜆 = 0
11025𝜇𝜇+10500𝜆𝜆+700 = 0 11025𝜇𝜇+10920𝜆𝜆+420 = 0
and
2 44
𝜆𝜆 = 3 𝜇𝜇 = −63
2 2 2
44 44 2 44 2
��10+20�− �� +�−100�− �−100� �� +�20+25�− �+20� ��
63 63 3 63 3
= 16.7 metres
Writes, in terms of a parameter, the position vector (or
coordinates) of one point on each of the two lines.
AnswerMarks Guidance
Condone use of same parameter.3.1a M1
Obtains, in terms of two parameters, a correct vector
AnswerMarks Guidance
between the two lines.1.1b A1
Sets up two scalar products for their and their
valid direction vectors.
AnswerMarks Guidance
𝒓𝒓𝟐𝟐−𝒓𝒓𝟏𝟏1.1a M1
Obtains correct parameter values.1.1b A1
Uses full method for required distance1.1b M1
Obtains correct distance to 2, 3 or 4 significant figures
with correct units.
AnswerMarks Guidance
Accept 1 significant figure if full method shown.3.2a A1
QMarking instructions AO
ALT
AnswerMarks Guidance
19(a)Finds a direction vector for the second wire. 3.4
10 −10
�0 �−�100�
Let be a vector perpendicula2r0 to both− w5ires.
𝑥𝑥
�𝑦𝑦�
𝑧𝑧 and
0 𝑥𝑥 20 𝑥𝑥
∴ �100�.�𝑦𝑦� = 0 �−100�.�𝑦𝑦� = 0
and
−20 𝑧𝑧 25 𝑧𝑧
⇒100𝑦𝑦−20𝑧𝑧 = 0 20𝑥𝑥−100𝑦𝑦+25𝑧𝑧 = 0
and
⇒𝑧𝑧 = 5𝑦𝑦 𝑥𝑥 = −1.25𝑦𝑦
perpendicular vector is
−1.25𝑦𝑦
∴ � 𝑦𝑦 �
5𝑦𝑦
unit perpendicular vector is
−1.25
2 2 2
⇒ � 1 �÷�(−1.25) +1 +5
5
a vector from 1st line to 2nd line is
10 0 10
�0 � −�0�= �0 �
20 0 20
distance between lines is
10 −1.25 21
∴ �0 �.� 1 �÷ 4
20 5
= 16.7 metres
AnswerMarks Guidance
Forms two equations for a perpendicular vector3.1a M1
Obtains two correct equations for a perpendicular vector1.1b A1
Obtains a correct normal vector1.1b A1
Finds the unit normal vector1.1a M1
Uses full method for required distance1.1b M1
Obtains correct distance to 2, 3 or 4 significant figures
with correct units.
AnswerMarks Guidance
Accept 1 significant figure if full method shown.3.2a A1

AnswerMarks Guidance
19(b)Suggests an improvement to the model.
Do not condone criticisms without refinements.3.5c B1
Total8
TOTAL80
Question 19:
--- 19(a) ---
19(a) | Finds a direction vector for the second wire.
Condone one error. | 3.4 | M1 | Direction vector for 2nd wire =
10 −10
�0 �−�100�
20 −5
and
0 0 10 20
𝒓𝒓𝟏𝟏 = �0�+𝜆𝜆�100� 𝒓𝒓𝟐𝟐 = �0 �+𝜇𝜇�−100�
0 −20 20 25
10+20𝜇𝜇
𝒓𝒓𝟐𝟐−𝒓𝒓𝟏𝟏 = �−100𝜇𝜇−100𝜆𝜆�
20+25𝜇𝜇+20𝜆𝜆
and
10+20𝜇𝜇 0 10+20𝜇𝜇 20
�−100𝜇𝜇−100𝜆𝜆�.�100�= 0 �−100𝜇𝜇−100𝜆𝜆�.�−100�= 0
20+25𝜇𝜇+20𝜆𝜆 −20 20+25𝜇𝜇+20𝜆𝜆 and2 5
−10000𝜇𝜇−10000𝜆𝜆−400 −500𝜇𝜇−400𝜆𝜆 = 0
200+400𝜇𝜇+10000𝜇𝜇+1 0 0a0n0d𝜆𝜆 +500+625𝜇𝜇+500𝜆𝜆 = 0
11025𝜇𝜇+10500𝜆𝜆+700 = 0 11025𝜇𝜇+10920𝜆𝜆+420 = 0
and
2 44
𝜆𝜆 = 3 𝜇𝜇 = −63
2 2 2
44 44 2 44 2
��10+20�− �� +�−100�− �−100� �� +�20+25�− �+20� ��
63 63 3 63 3
= 16.7 metres
Writes, in terms of a parameter, the position vector (or
coordinates) of one point on each of the two lines.
Condone use of same parameter. | 3.1a | M1
Obtains, in terms of two parameters, a correct vector
between the two lines. | 1.1b | A1
Sets up two scalar products for their and their
valid direction vectors.
𝒓𝒓𝟐𝟐−𝒓𝒓𝟏𝟏 | 1.1a | M1
Obtains correct parameter values. | 1.1b | A1
Uses full method for required distance | 1.1b | M1
Obtains correct distance to 2, 3 or 4 significant figures
with correct units.
Accept 1 significant figure if full method shown. | 3.2a | A1
Q | Marking instructions | AO | Mark | Typical solution
ALT
19(a) | Finds a direction vector for the second wire. | 3.4 | M1 | Direction vector for 2nd wire =
10 −10
�0 �−�100�
Let be a vector perpendicula2r0 to both− w5ires.
𝑥𝑥
�𝑦𝑦�
𝑧𝑧 and
0 𝑥𝑥 20 𝑥𝑥
∴ �100�.�𝑦𝑦� = 0 �−100�.�𝑦𝑦� = 0
and
−20 𝑧𝑧 25 𝑧𝑧
⇒100𝑦𝑦−20𝑧𝑧 = 0 20𝑥𝑥−100𝑦𝑦+25𝑧𝑧 = 0
and
⇒𝑧𝑧 = 5𝑦𝑦 𝑥𝑥 = −1.25𝑦𝑦
perpendicular vector is
−1.25𝑦𝑦
∴ � 𝑦𝑦 �
5𝑦𝑦
unit perpendicular vector is
−1.25
2 2 2
⇒ � 1 �÷�(−1.25) +1 +5
5
a vector from 1st line to 2nd line is
10 0 10
�0 � −�0�= �0 �
20 0 20
distance between lines is
10 −1.25 21
∴ �0 �.� 1 �÷ 4
20 5
= 16.7 metres
Forms two equations for a perpendicular vector | 3.1a | M1
Obtains two correct equations for a perpendicular vector | 1.1b | A1
Obtains a correct normal vector | 1.1b | A1
Finds the unit normal vector | 1.1a | M1
Uses full method for required distance | 1.1b | M1
Obtains correct distance to 2, 3 or 4 significant figures
with correct units.
Accept 1 significant figure if full method shown. | 3.2a | A1
--- 19(b) ---
19(b) | Suggests an improvement to the model.
Do not condone criticisms without refinements. | 3.5c | B1 | Model the wires as curves
Total | 8
TOTAL | 80
A theme park has two zip wires.

Sarah models the two zip wires as straight lines using coordinates in metres.

The ends of one wire are located at $(0, 0, 0)$ and $(0, 100, -20)$

The ends of the other wire are located at $(10, 0, 20)$ and $(-10, 100, -5)$

\begin{enumerate}[label=(\alph*)]
\item Use Sarah's model to find the shortest distance between the zip wires.
[7 marks]

\item State one way in which Sarah's model could be refined.
[1 mark]
\end{enumerate}

\hfill \mbox{\textit{AQA Further AS Paper 1 2018 Q19 [8]}}