AQA Further AS Paper 1 2018 June — Question 11 3 marks

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2018
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas Between Curves
TypeCurve with Horizontal Line
DifficultyChallenging +1.2 This is a Further Maths question requiring integration to find areas and setting up an equation where two regions have equal area. While it involves a cubic and requires careful setup of the integral equation, the technique is standard: integrate the cubic, apply limits, and solve the resulting equation. The 3-mark allocation suggests a straightforward application of integration skills with some algebraic manipulation, making it moderately above average difficulty but not requiring novel insight.
Spec1.08f Area between two curves: using integration

Four finite regions \(A\), \(B\), \(C\) and \(D\) are enclosed by the curve with equation $$y = x^3 - 7x^2 + 11x + 6$$ and the lines \(y = k\), \(x = 1\) and \(x = 4\), as shown in the diagram below. \includegraphics{figure_11} The areas of \(B\) and \(C\) are equal. Find the value of \(k\). [3 marks]

Question 11:
AnswerMarks Guidance
11States integral(s) of the cubic with limits that include 1 and 4 1.1a
1 3 2
mean=𝑘𝑘 = �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6) 𝑑𝑑𝑥𝑥
4−1
1
4 3 2 4
1 𝑥𝑥 7𝑥𝑥 11𝑥𝑥
∴ 𝑘𝑘 = � − + +6𝑥𝑥�
3 4 3 2 1
4 3 2 4 3 2
1 4 7×4 11×4 1 1 7×1 11×1
= � − + +6×4�− � − + +6×1�
3 4 3 2 3 4 3 2
1 80 1 113
= × − ×
3 3 3 12
= 5.75
Integrates the function and substitutes correct limits.
Condone one incorrect term.
4
AnswerMarks Guidance
3 2 691.1a M1
Note: �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6) 𝑑𝑑𝑥𝑥 = ⇒ M1M1
4
1
Obtains the correct value of k.
Do not apply ISW.
AnswerMarks Guidance
NMS can score 3/3.1.1b A1
Total3
4
3 2
�(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6−𝑘𝑘) 𝑑𝑑𝑥𝑥 = 0
1
4 3 2 4
𝑥𝑥 7𝑥𝑥 11𝑥𝑥
� − + +6𝑥𝑥−𝑘𝑘𝑥𝑥� = 0
4 3 2 1
4 3 2
4 7×4 11×4 1 7 11
� − + +6×4−𝑘𝑘×4�−� − + +6−𝑘𝑘�=0
4 3 2 4 3 2
448 113
64− +88+24−4𝑘𝑘− +𝑘𝑘 = 0
3 12
69
= 3𝑘𝑘
4
Area B = Area C
𝑝𝑝 4
3 2 3 2
∴ �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6−𝑘𝑘) 𝑑𝑑𝑥𝑥 = �(𝑘𝑘−𝑥𝑥 +7𝑥𝑥 −11𝑥𝑥−6) 𝑑𝑑𝑥𝑥
1 𝑝𝑝
4 3 2 𝑝𝑝 4 3 2 4
𝑥𝑥 7𝑥𝑥 11𝑥𝑥 𝑥𝑥 7𝑥𝑥 11𝑥𝑥
� − + +6𝑥𝑥−𝑘𝑘𝑥𝑥� = �𝑘𝑘𝑥𝑥− + − −6𝑥𝑥�
4 3 2 1 4 3 2 𝑝𝑝
4 3 2
𝑝𝑝 7𝑝𝑝 11𝑝𝑝 1 7 11
� − + +6𝑝𝑝−𝑘𝑘𝑝𝑝�−� − + +6−𝑘𝑘�
4 3 2 4 3 2
4 3 2
7×64 11×16 𝑝𝑝 7𝑝𝑝 11𝑝𝑝
= �4𝑘𝑘−64+ − −24�−�𝑘𝑘𝑝𝑝− + − −6𝑝𝑝�
3 2 4 3 2
1 7 11 448
− + − −6+𝑘𝑘 = 4𝑘𝑘−64+ −88−24
4 3 2 3
69
= 3𝑘𝑘
4
AnswerMarks Guidance
QMarking instructions AO
Question 11:
11 | States integral(s) of the cubic with limits that include 1 and 4 | 1.1a | M1 | 4
1 3 2
mean=𝑘𝑘 = �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6) 𝑑𝑑𝑥𝑥
4−1
1
4 3 2 4
1 𝑥𝑥 7𝑥𝑥 11𝑥𝑥
∴ 𝑘𝑘 = � − + +6𝑥𝑥�
3 4 3 2 1
4 3 2 4 3 2
1 4 7×4 11×4 1 1 7×1 11×1
= � − + +6×4�− � − + +6×1�
3 4 3 2 3 4 3 2
1 80 1 113
= × − ×
3 3 3 12
= 5.75
Integrates the function and substitutes correct limits.
Condone one incorrect term.
4
3 2 69 | 1.1a | M1
Note: �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6) 𝑑𝑑𝑥𝑥 = ⇒ M1M1
4
1
Obtains the correct value of k.
Do not apply ISW.
NMS can score 3/3. | 1.1b | A1
Total | 3
4
3 2
�(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6−𝑘𝑘) 𝑑𝑑𝑥𝑥 = 0
1
4 3 2 4
𝑥𝑥 7𝑥𝑥 11𝑥𝑥
� − + +6𝑥𝑥−𝑘𝑘𝑥𝑥� = 0
4 3 2 1
4 3 2
4 7×4 11×4 1 7 11
� − + +6×4−𝑘𝑘×4�−� − + +6−𝑘𝑘�=0
4 3 2 4 3 2
448 113
64− +88+24−4𝑘𝑘− +𝑘𝑘 = 0
3 12
69
= 3𝑘𝑘
4
Area B = Area C
𝑝𝑝 4
3 2 3 2
∴ �(𝑥𝑥 −7𝑥𝑥 +11𝑥𝑥+6−𝑘𝑘) 𝑑𝑑𝑥𝑥 = �(𝑘𝑘−𝑥𝑥 +7𝑥𝑥 −11𝑥𝑥−6) 𝑑𝑑𝑥𝑥
1 𝑝𝑝
4 3 2 𝑝𝑝 4 3 2 4
𝑥𝑥 7𝑥𝑥 11𝑥𝑥 𝑥𝑥 7𝑥𝑥 11𝑥𝑥
� − + +6𝑥𝑥−𝑘𝑘𝑥𝑥� = �𝑘𝑘𝑥𝑥− + − −6𝑥𝑥�
4 3 2 1 4 3 2 𝑝𝑝
4 3 2
𝑝𝑝 7𝑝𝑝 11𝑝𝑝 1 7 11
� − + +6𝑝𝑝−𝑘𝑘𝑝𝑝�−� − + +6−𝑘𝑘�
4 3 2 4 3 2
4 3 2
7×64 11×16 𝑝𝑝 7𝑝𝑝 11𝑝𝑝
= �4𝑘𝑘−64+ − −24�−�𝑘𝑘𝑝𝑝− + − −6𝑝𝑝�
3 2 4 3 2
1 7 11 448
− + − −6+𝑘𝑘 = 4𝑘𝑘−64+ −88−24
4 3 2 3
69
= 3𝑘𝑘
4
Q | Marking instructions | AO | Mark | Typical solution
Four finite regions $A$, $B$, $C$ and $D$ are enclosed by the curve with equation
$$y = x^3 - 7x^2 + 11x + 6$$
and the lines $y = k$, $x = 1$ and $x = 4$, as shown in the diagram below.

\includegraphics{figure_11}

The areas of $B$ and $C$ are equal.

Find the value of $k$.
[3 marks]

\hfill \mbox{\textit{AQA Further AS Paper 1 2018 Q11 [3]}}