OCR MEI Paper 2 2022 June — Question 14 8 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2022
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeRectangle bounds for definite integral
DifficultyStandard +0.3 This is a straightforward numerical integration question using lower and upper rectangular bounds. Parts (a)-(c) involve basic arithmetic with given coordinates, part (d) requires reading from a table and simple subtraction, and part (e) tests conceptual understanding of refinement. All steps are routine applications of standard A-level techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.08g Integration as limit of sum: Riemann sums

Fig. 14.1 shows the curve with equation \(y = \frac{1}{1 + x^2}\), together with 5 rectangles of equal width. \includegraphics{figure_14_1} Fig. 14.2 shows the coordinates of the points A, B, C, D, E and F. \includegraphics{figure_14_2}
  1. Use the 5 rectangles shown in Fig. 14.1 and the information in Fig. 14.2 to show that a lower bound for \(\int_0^1 \frac{1}{1 + x^2}\,dx\) is 0.7337, correct to 4 decimal places. [2]
  2. Use the 5 rectangles shown in Fig. 14.1 and the information in Fig. 14.2 to calculate an upper bound for \(\int_0^1 \frac{1}{1 + x^2}\,dx\) correct to 4 decimal places. [2]
  3. Hence find the length of the interval in which your answers to parts (a) and (b) indicate the value of \(\int_0^1 \frac{1}{1 + x^2}\,dx\) lies. [1]
Amit uses \(n\) rectangles, each of width \(\frac{1}{n}\), to calculate upper and lower bounds for \(\int_0^1 \frac{1}{1 + x^2}\,dx\), using different values of \(n\). His results are shown in Fig. 14.3. \includegraphics{figure_14_3}
  1. Find the length of the smallest interval in which Amit now knows \(\int_0^1 \frac{1}{1 + x^2}\,dx\) lies. [2]
  2. Without doing any calculation, explain how Amit could find a smaller interval which contains the value of \(\int_0^1 \frac{1}{1 + x^2}\,dx\). [1]

Question 14:
AnswerMarks Guidance
14(a) 0.2 × {0.96154 + 0.86207 + 0.73529 +
0.60976 + 0.5} soi
AnswerMarks
0.73373… ≈ 0.7337 AGM1
A12.1
2.4allow M1A1 for calculation of exact values using formula in
parts (a) and (b)
need to see 0.73373… as well as 0.7337 for A1
[2]
AnswerMarks Guidance
14(b) 0.2 × {1 + 0.96154 + 0.86207 + 0.73529 +
0.60976}
AnswerMarks
0.8337 correct to 4 dpM1
A11.1
1.1or (3.66866 - 0.5 + 1) × 0.2
[2]
AnswerMarks Guidance
14(c) 0.1
in part (b)
[1]
AnswerMarks Guidance
14(d) 0.79162 ‒ 0.77912
0.0125M1
A13.1a
2.4if M0 allow SC1 for correct interval identified
eg 0.77912 to 0.79162
[2]
AnswerMarks Guidance
14(e) increase n oe
use rectangles of smaller width oeB1 2.2a
eg just ‘smaller’ rectangles – need to specify width reduction
[1]
Question 14:
14 | (a) | 0.2 × {0.96154 + 0.86207 + 0.73529 +
0.60976 + 0.5} soi
0.73373… ≈ 0.7337 AG | M1
A1 | 2.1
2.4 | allow M1A1 for calculation of exact values using formula in
parts (a) and (b)
need to see 0.73373… as well as 0.7337 for A1
[2]
14 | (b) | 0.2 × {1 + 0.96154 + 0.86207 + 0.73529 +
0.60976}
0.8337 correct to 4 dp | M1
A1 | 1.1
1.1 | or (3.66866 - 0.5 + 1) × 0.2
[2]
14 | (c) | 0.1 | B1 | 1.1 | FT their 0.8337(32) ‒ 0.7337(32), dependent on award of M1
in part (b)
[1]
14 | (d) | 0.79162 ‒ 0.77912
0.0125 | M1
A1 | 3.1a
2.4 | if M0 allow SC1 for correct interval identified
eg 0.77912 to 0.79162
[2]
14 | (e) | increase n oe
use rectangles of smaller width oe | B1 | 2.2a | do not allow eg reduce interval
eg just ‘smaller’ rectangles – need to specify width reduction
[1]
Fig. 14.1 shows the curve with equation $y = \frac{1}{1 + x^2}$, together with 5 rectangles of equal width.

\includegraphics{figure_14_1}

Fig. 14.2 shows the coordinates of the points A, B, C, D, E and F.

\includegraphics{figure_14_2}

\begin{enumerate}[label=(\alph*)]
\item Use the 5 rectangles shown in Fig. 14.1 and the information in Fig. 14.2 to show that a lower bound for $\int_0^1 \frac{1}{1 + x^2}\,dx$ is 0.7337, correct to 4 decimal places. [2]
\item Use the 5 rectangles shown in Fig. 14.1 and the information in Fig. 14.2 to calculate an upper bound for $\int_0^1 \frac{1}{1 + x^2}\,dx$ correct to 4 decimal places. [2]
\item Hence find the length of the interval in which your answers to parts (a) and (b) indicate the value of $\int_0^1 \frac{1}{1 + x^2}\,dx$ lies. [1]
\end{enumerate}

Amit uses $n$ rectangles, each of width $\frac{1}{n}$, to calculate upper and lower bounds for $\int_0^1 \frac{1}{1 + x^2}\,dx$, using different values of $n$. His results are shown in Fig. 14.3.

\includegraphics{figure_14_3}

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item Find the length of the smallest interval in which Amit now knows $\int_0^1 \frac{1}{1 + x^2}\,dx$ lies. [2]
\item Without doing any calculation, explain how Amit could find a smaller interval which contains the value of $\int_0^1 \frac{1}{1 + x^2}\,dx$. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 2 2022 Q14 [8]}}