CAIE Further Paper 2 2021 November — Question 7 11 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2021
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeIntegrating factor with non-standard form
DifficultyChallenging +1.8 This Further Maths question requires recognizing the non-standard form, verifying a given integrating factor involving √(x²-1), then applying it to solve the DE with an initial condition. The algebraic manipulation with nested radicals and the verification process demand careful technique beyond standard integrating factor problems, but the integrating factor is provided in part (a), reducing the problem-solving burden.
Spec4.10c Integrating factor: first order equations

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  1. Show that an appropriate integrating factor for $$\sqrt { x ^ { 2 } - 1 } \frac { d y } { d x } + y = x ^ { 2 } - x \sqrt { x ^ { 2 } - 1 }$$ is \(x + \sqrt { x ^ { 2 } - 1 }\).
  2. Hence find the solution of the differential equation $$\sqrt { x ^ { 2 } - 1 } \frac { d y } { d x } + y = x ^ { 2 } - x \sqrt { x ^ { 2 } - 1 }$$ for which \(y = 1\) when \(x = \frac { 5 } { 4 }\). Give your answer in the form \(y = f ( x )\).

Question 7(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{dy}{dx} + \frac{1}{\sqrt{x^2-1}}\,y = \frac{x^2 - x\sqrt{x^2-1}}{\sqrt{x^2-1}}\)B1 Divides through by \(\sqrt{x^2-1}\)
\(e^{\int \frac{1}{\sqrt{x^2-1}}\,dx} = e^{\cosh^{-1}x}\)M1 A1 Finds integrating factor. M1 for correct form \(e^{a\int \frac{1}{\sqrt{x^2-1}}\,dx}\) where \(a\) is a non-zero constant
\(x + \sqrt{x^2-1}\)A1 AG
4
Question 7(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{d}{dx}\!\left(y\!\left(x + \sqrt{x^2-1}\right)\right) = \frac{x}{\sqrt{x^2-1}}\)M1 A1 Correct form on LHS and simplifies RHS
\(y\!\left(x + \sqrt{x^2-1}\right) = \sqrt{x^2-1} + C\)M1 A1 Integrates RHS. For M1, needs to integrate non-zero multiple of \(\frac{x}{\sqrt{x^2-1}}\)
\(2 = \frac{3}{4} + C\) leading to \(C = \frac{5}{4}\)M1 Substitutes initial conditions
\(y = \dfrac{\sqrt{x^2-1} + \frac{5}{4}}{x + \sqrt{x^2-1}}\)M1 A1 Divides through by coefficient of \(y\)
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## Question 7(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{dy}{dx} + \frac{1}{\sqrt{x^2-1}}\,y = \frac{x^2 - x\sqrt{x^2-1}}{\sqrt{x^2-1}}$ | B1 | Divides through by $\sqrt{x^2-1}$ |
| $e^{\int \frac{1}{\sqrt{x^2-1}}\,dx} = e^{\cosh^{-1}x}$ | M1 A1 | Finds integrating factor. M1 for correct form $e^{a\int \frac{1}{\sqrt{x^2-1}}\,dx}$ where $a$ is a non-zero constant |
| $x + \sqrt{x^2-1}$ | A1 | AG |
| | **4** | |

## Question 7(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{d}{dx}\!\left(y\!\left(x + \sqrt{x^2-1}\right)\right) = \frac{x}{\sqrt{x^2-1}}$ | M1 A1 | Correct form on LHS and simplifies RHS |
| $y\!\left(x + \sqrt{x^2-1}\right) = \sqrt{x^2-1} + C$ | M1 A1 | Integrates RHS. For M1, needs to integrate non-zero multiple of $\frac{x}{\sqrt{x^2-1}}$ |
| $2 = \frac{3}{4} + C$ leading to $C = \frac{5}{4}$ | M1 | Substitutes initial conditions |
| $y = \dfrac{\sqrt{x^2-1} + \frac{5}{4}}{x + \sqrt{x^2-1}}$ | M1 A1 | Divides through by coefficient of $y$ |
| | **7** | |
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\begin{enumerate}[label=(\alph*)]
\item Show that an appropriate integrating factor for

$$\sqrt { x ^ { 2 } - 1 } \frac { d y } { d x } + y = x ^ { 2 } - x \sqrt { x ^ { 2 } - 1 }$$

is $x + \sqrt { x ^ { 2 } - 1 }$.
\item Hence find the solution of the differential equation

$$\sqrt { x ^ { 2 } - 1 } \frac { d y } { d x } + y = x ^ { 2 } - x \sqrt { x ^ { 2 } - 1 }$$

for which $y = 1$ when $x = \frac { 5 } { 4 }$. Give your answer in the form $y = f ( x )$.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 2 2021 Q7 [11]}}