CAIE Further Paper 2 2021 November — Question 2 6 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInvariant lines and eigenvalues and vectors
TypeUse Cayley-Hamilton for matrix power
DifficultyStandard +0.8 This is a standard Cayley-Hamilton theorem application requiring finding the characteristic equation of a 3×3 matrix, then manipulating it to express A^4 in terms of lower powers. The triangular structure simplifies eigenvalue finding, but the algebraic manipulation to reach the specific form requires careful work across multiple steps, making it moderately challenging for Further Maths.
Spec4.03h Determinant 2x2: calculation

2 The matrix \(\mathbf { A }\) is given by $$\mathbf { A } = \left( \begin{array} { r r r } - 1 & 2 & 12 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{array} \right) .$$ Use the characteristic equation of \(\mathbf { A }\) to show that $$\mathbf { A } ^ { 4 } = p \mathbf { A } ^ { 2 } + q \mathbf { l }$$ where \(p\) and \(q\) are integers to be determined.

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\((\lambda+1)(\lambda-1)(\lambda-3)=\lambda^3-3\lambda^2-\lambda+3[=0]\)M1 A1 Finds characteristic equation.
\(\mathbf{A}^3-3\mathbf{A}^2-\mathbf{A}+3\mathbf{I}=0 \Rightarrow \mathbf{A}^4-3\mathbf{A}^3-\mathbf{A}^2+3\mathbf{A}=0\)M1 A1 Substitutes \(\mathbf{A}\) and multiplies through by \(\mathbf{A}\).
\(\mathbf{A}^4=3(3\mathbf{A}^2+\mathbf{A}-3\mathbf{I})+\mathbf{A}^2-3\mathbf{A}=10\mathbf{A}^2-9\mathbf{I}\)M1 A1 Substitutes \(\mathbf{A}^3\).
Total6
**Question 2:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(\lambda+1)(\lambda-1)(\lambda-3)=\lambda^3-3\lambda^2-\lambda+3[=0]$ | M1 A1 | Finds characteristic equation. |
| $\mathbf{A}^3-3\mathbf{A}^2-\mathbf{A}+3\mathbf{I}=0 \Rightarrow \mathbf{A}^4-3\mathbf{A}^3-\mathbf{A}^2+3\mathbf{A}=0$ | M1 A1 | Substitutes $\mathbf{A}$ and multiplies through by $\mathbf{A}$. |
| $\mathbf{A}^4=3(3\mathbf{A}^2+\mathbf{A}-3\mathbf{I})+\mathbf{A}^2-3\mathbf{A}=10\mathbf{A}^2-9\mathbf{I}$ | M1 A1 | Substitutes $\mathbf{A}^3$. |
| **Total** | **6** | |

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2 The matrix $\mathbf { A }$ is given by

$$\mathbf { A } = \left( \begin{array} { r r r } 
- 1 & 2 & 12 \\
0 & 1 & 0 \\
0 & 0 & 3
\end{array} \right) .$$

Use the characteristic equation of $\mathbf { A }$ to show that

$$\mathbf { A } ^ { 4 } = p \mathbf { A } ^ { 2 } + q \mathbf { l }$$

where $p$ and $q$ are integers to be determined.\\

\hfill \mbox{\textit{CAIE Further Paper 2 2021 Q2 [6]}}