Easy -1.8 This is a 1-mark multiple choice question testing only the basic definition that a normal is perpendicular to the tangent. Since f'(3)=0 means horizontal tangent, the normal must be vertical (x=3). No calculation required, just recall of a single concept.
A curve with equation \(y = f(x)\) passes through the point \((3, 7)\)
Given that \(f'(3) = 0\) find the equation of the normal to the curve at \((3, 7)\)
Circle your answer.
[1 mark]
\(y = \frac{7}{3}x\) \(y = 0\) \(x = 3\) \(x = 7\)
A curve with equation $y = f(x)$ passes through the point $(3, 7)$
Given that $f'(3) = 0$ find the equation of the normal to the curve at $(3, 7)$
Circle your answer.
[1 mark]
$y = \frac{7}{3}x$ $y = 0$ $x = 3$ $x = 7$
\hfill \mbox{\textit{AQA Paper 3 2023 Q3 [1]}}