Easy -2.0 This is a simple recall question worth 1 mark requiring only knowledge that arccos has domain [-1,1] and range [0,π], so the endpoint P is at (-1,π). No calculation or problem-solving is needed, just basic function knowledge from the specification.
The graph of \(y = \arccos x\) is shown.
\includegraphics{figure_1}
State the coordinates of the end point \(P\).
Circle your answer.
[1 mark]
\((-\pi, 1)\) \quad \((-1, \pi)\) \quad \(\left(-\frac{\pi}{2}, 1\right)\) \quad \(\left(-1, \frac{\pi}{2}\right)\)
The graph of $y = \arccos x$ is shown.
\includegraphics{figure_1}
State the coordinates of the end point $P$.
Circle your answer.
[1 mark]
$(-\pi, 1)$ \quad $(-1, \pi)$ \quad $\left(-\frac{\pi}{2}, 1\right)$ \quad $\left(-1, \frac{\pi}{2}\right)$
\hfill \mbox{\textit{AQA Paper 3 2021 Q1 [1]}}