OCR H240/03 2023 June — Question 8 4 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2023
SessionJune
Marks4
PaperDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeParticle motion: 2D constant acceleration
DifficultyModerate -0.8 This is a straightforward kinematics problem requiring only the constant acceleration formula v = u + at. Students substitute known values to find the initial velocity vector, then calculate its magnitude. It's more routine than average A-level questions since it involves direct application of a single formula with no problem-solving insight required.
Spec1.10c Magnitude and direction: of vectors1.10h Vectors in kinematics: uniform acceleration in vector form

A particle \(P\) moves with constant acceleration \((3\mathbf{i} - 2\mathbf{j}) \text{ms}^{-2}\). At time \(t = 4\) seconds, \(P\) has velocity \(6\mathbf{i} \text{ms}^{-1}\). Determine the speed of \(P\) at time \(t = 0\) seconds. [4]

A particle $P$ moves with constant acceleration $(3\mathbf{i} - 2\mathbf{j}) \text{ms}^{-2}$. At time $t = 4$ seconds, $P$ has velocity $6\mathbf{i} \text{ms}^{-1}$.

Determine the speed of $P$ at time $t = 0$ seconds. [4]

\hfill \mbox{\textit{OCR H240/03 2023 Q8 [4]}}