OCR H240/03 2023 June — Question 2 5 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2023
SessionJune
Marks5
PaperDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyModerate -0.3 This is a standard two-part question on the R-formula (harmonic form) with straightforward application. Part (a) requires routine use of R cos α = 4, R sin α = 3 to find R = 5 and α ≈ 36.87°. Part (b) is a direct substitution leading to a single inverse sine calculation. The question is slightly easier than average because it follows a completely standard template with no complications or novel elements.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

  1. Express \(3 \sin x - 4 \cos x\) in the form \(R \sin(x - \alpha)\), where \(R > 0\) and \(0° < \alpha < 90°\). Give the value of \(\alpha\) correct to 4 significant figures. [3]
  2. Hence solve the equation \(3 \sin x - 4 \cos x = 2\) for \(0° < x < 90°\), giving your answer correct to 3 significant figures. [2]

\begin{enumerate}[label=(\alph*)]
\item Express $3 \sin x - 4 \cos x$ in the form $R \sin(x - \alpha)$, where $R > 0$ and $0° < \alpha < 90°$. Give the value of $\alpha$ correct to 4 significant figures. [3]

\item Hence solve the equation $3 \sin x - 4 \cos x = 2$ for $0° < x < 90°$, giving your answer correct to 3 significant figures. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR H240/03 2023 Q2 [5]}}