Standard +0.3 This is a straightforward application of De Moivre's theorem to find cube roots. Students must convert to modulus-argument form, divide the argument by 3, and find three roots by adding 2π/3. While it's a Further Maths topic, it's a standard textbook exercise requiring only methodical application of a well-practiced technique with no novel insight needed.
1 Find the roots of the equation \(z ^ { 3 } = - 108 \sqrt { 3 } + 108\) i, giving your answers in the form \(r ( \cos \theta + \mathrm { i } \sin \theta )\), where \(r > 0\) and \(0 < \theta < 2 \pi\).
1 Find the roots of the equation $z ^ { 3 } = - 108 \sqrt { 3 } + 108$ i, giving your answers in the form $r ( \cos \theta + \mathrm { i } \sin \theta )$, where $r > 0$ and $0 < \theta < 2 \pi$.\\
\hfill \mbox{\textit{CAIE Further Paper 2 2024 Q1 [5]}}