OCR FP2 2010 January — Question 8 10 marks

Exam BoardOCR
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeRational functions with parameters: analysis depending on parameter sign/range
DifficultyStandard +0.3 This is a straightforward FP2 curve sketching question involving rational functions. Part (i) requires identifying asymptotes (routine), part (ii) uses calculus to find the minimum value (standard optimization), and part (iii) finds stationary points by differentiation using quotient rule. While it requires multiple techniques and some algebraic manipulation, all steps follow standard procedures without requiring novel insight or particularly complex reasoning.
Spec1.02n Sketch curves: simple equations including polynomials1.07n Stationary points: find maxima, minima using derivatives

The equation of a curve is $$y = \frac{kx}{(x-1)^2},$$ where \(k\) is a positive constant.
  1. Write down the equations of the asymptotes of the curve. [2]
  2. Show that \(y \geq -\frac{1}{4}k\). [4]
  3. Show that the \(x\)-coordinate of the stationary point of the curve is independent of \(k\), and sketch the curve. [4]

(i)
AnswerMarks
Get \(x = 1, y = 0\)B1, B1
(ii)
AnswerMarks Guidance
Rewrite as quadratic in \(x\)M1 \((x^2y - x(2y+k) + y = 0)\)
Use \(b^2 - 4ac \geq 0\) for all real \(x\)M1 Allow \(>, =\) here
Get correct inequalityA1 \(4ky + k^2 \geq 0\)
State use of \(k>0\) to A.G.A1
SC Use differentiation (parts (ii) and (iii))M1
Attempt prod/quotient ruleM1
Solve \(= 0\) for \(x = -1\)A1
Use \(x = -1\) only (reject x=1), \(y = -\frac{k}{4}\)A1
Fully justify minimumB1
Attempt to justify for all \(x\)M1
Clearly get A.G.A1
(iii)
AnswerMarks
Replace \(y = -\frac{k}{4}\) in quadratic in \(x\)M1
Get \(x = -1\) onlyA1
B1Through origin with minimum at \((-1, -\frac{k}{4})\) seen or given in the answer
B1Correct shape (asymptotes and approaches)
SC (Start again)
AnswerMarks
Differentiate and solve \(\frac{dy}{dx} = 0\) for at least one x-value, independent of \(k\)M1
Get \(x = -1\) onlyA1
## (i)
Get $x = 1, y = 0$ | B1, B1 | 

## (ii)
Rewrite as quadratic in $x$ | M1 | $(x^2y - x(2y+k) + y = 0)$
Use $b^2 - 4ac \geq 0$ for all real $x$ | M1 | Allow $>, =$ here
Get correct inequality | A1 | $4ky + k^2 \geq 0$
State use of $k>0$ to A.G. | A1 | 

**SC** Use differentiation (parts (ii) and (iii)) | M1 | 
Attempt prod/quotient rule | M1 | 
Solve $= 0$ for $x = -1$ | A1 | 
Use $x = -1$ only (reject x=1), $y = -\frac{k}{4}$ | A1 | 
Fully justify minimum | B1 | 
Attempt to justify for all $x$ | M1 | 
Clearly get A.G. | A1 | 

## (iii)
Replace $y = -\frac{k}{4}$ in quadratic in $x$ | M1 | 
Get $x = -1$ only | A1 | 

| B1 | Through origin with minimum at $(-1, -\frac{k}{4})$ seen or given in the answer

| B1 | Correct shape (asymptotes and approaches)

**SC** (Start again)
Differentiate and solve $\frac{dy}{dx} = 0$ for at least one x-value, independent of $k$ | M1 | 
Get $x = -1$ only | A1 | 

---
The equation of a curve is
$$y = \frac{kx}{(x-1)^2},$$
where $k$ is a positive constant.

\begin{enumerate}[label=(\roman*)]
\item Write down the equations of the asymptotes of the curve. [2]

\item Show that $y \geq -\frac{1}{4}k$. [4]

\item Show that the $x$-coordinate of the stationary point of the curve is independent of $k$, and sketch the curve. [4]
\end{enumerate}

\hfill \mbox{\textit{OCR FP2 2010 Q8 [10]}}