OCR FP2 2010 January — Question 4 7 marks

Exam BoardOCR
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypePolar curve with exponential function
DifficultyStandard +0.8 This is an FP2 polar coordinates question requiring a sketch of an exponential spiral and derivation of an area formula. Part (i) is straightforward. Part (ii) requires applying the polar area formula, substituting the curve equation, integrating an exponential, then manipulating to express the result in terms of r₁ and r₂ rather than θ₁ and θ₂—this algebraic transformation requires insight but follows standard FP2 techniques. Moderately challenging for Further Maths.
Spec4.09b Sketch polar curves: r = f(theta)4.09c Area enclosed: by polar curve

The equation of a curve, in polar coordinates, is $$r = e^{-2\theta}, \quad \text{for } 0 \leq \theta \leq \pi.$$
  1. Sketch the curve, stating the polar coordinates of the point at which \(r\) takes its greatest value. [2]
  2. The pole is \(O\) and points \(P\) and \(Q\), with polar coordinates \((r_1, \theta_1)\) and \((r_2, \theta_2)\) respectively, lie on the curve. Given that \(\theta_2 > \theta_1\), show that the area of the region enclosed by the curve and the lines \(OP\) and \(OQ\) can be expressed as \(k(r_1^2 - r_2^2)\), where \(k\) is a constant to be found. [5]

The equation of a curve, in polar coordinates, is
$$r = e^{-2\theta}, \quad \text{for } 0 \leq \theta \leq \pi.$$

\begin{enumerate}[label=(\roman*)]
\item Sketch the curve, stating the polar coordinates of the point at which $r$ takes its greatest value. [2]

\item The pole is $O$ and points $P$ and $Q$, with polar coordinates $(r_1, \theta_1)$ and $(r_2, \theta_2)$ respectively, lie on the curve. Given that $\theta_2 > \theta_1$, show that the area of the region enclosed by the curve and the lines $OP$ and $OQ$ can be expressed as $k(r_1^2 - r_2^2)$, where $k$ is a constant to be found. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR FP2 2010 Q4 [7]}}