OCR MEI FP1 2007 June — Question 6 6 marks

Exam BoardOCR MEI
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeMethod of differences with given identity
DifficultyModerate -0.8 Part (i) is trivial algebraic verification requiring only finding a common denominator. Part (ii) is a standard textbook application of the method of differences with telescoping series—a routine FP1 technique with no problem-solving required. The calculation is straightforward once the pattern is recognized, making this significantly easier than average A-level questions.
Spec4.06b Method of differences: telescoping series

  1. Show that \(\frac{1}{r+2} - \frac{1}{r+3} = \frac{1}{(r+2)(r+3)}\). [2]
  2. Hence use the method of differences to find \(\frac{1}{3 \times 4} + \frac{1}{4 \times 5} + \frac{1}{5 \times 6} + \ldots + \frac{1}{52 \times 53}\). [4]

\begin{enumerate}[label=(\roman*)]
\item Show that $\frac{1}{r+2} - \frac{1}{r+3} = \frac{1}{(r+2)(r+3)}$. [2]

\item Hence use the method of differences to find $\frac{1}{3 \times 4} + \frac{1}{4 \times 5} + \frac{1}{5 \times 6} + \ldots + \frac{1}{52 \times 53}$. [4]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI FP1 2007 Q6 [6]}}