OCR FP1 — Question 7 10 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
Topic3x3 Matrices
TypeFind inverse then solve system
DifficultyStandard +0.3 This is a standard FP1 matrix question covering determinants, matrix inverses, and solving simultaneous equations. Part (i) requires computing a 3×3 determinant and setting it to zero (routine). Part (ii) involves finding the inverse using the adjugate method (standard algorithm). Part (iii) applies the inverse to solve equations (direct application). While it's Further Maths content, these are textbook exercises requiring methodical calculation rather than insight, making it slightly easier than an average A-level question overall.
Spec4.03j Determinant 3x3: calculation4.03o Inverse 3x3 matrix4.03r Solve simultaneous equations: using inverse matrix

The matrix \(\mathbf{B}\) is given by \(\mathbf{B} = \begin{pmatrix} a & 1 & 3 \\ 2 & 1 & -1 \\ 0 & 1 & 2 \end{pmatrix}\).
  1. Given that \(\mathbf{B}\) is singular, show that \(a = -\frac{2}{3}\). [3]
  2. Given instead that \(\mathbf{B}\) is non-singular, find the inverse matrix \(\mathbf{B}^{-1}\). [4]
  3. Hence, or otherwise, solve the equations \begin{align} -x + y + 3z &= 1,
    2x + y - z &= 4,
    y + 2z &= -1. \end{align} [3]

The matrix $\mathbf{B}$ is given by $\mathbf{B} = \begin{pmatrix} a & 1 & 3 \\ 2 & 1 & -1 \\ 0 & 1 & 2 \end{pmatrix}$.

\begin{enumerate}[label=(\roman*)]
\item Given that $\mathbf{B}$ is singular, show that $a = -\frac{2}{3}$. [3]
\item Given instead that $\mathbf{B}$ is non-singular, find the inverse matrix $\mathbf{B}^{-1}$. [4]
\item Hence, or otherwise, solve the equations
\begin{align}
-x + y + 3z &= 1, \\
2x + y - z &= 4, \\
y + 2z &= -1.
\end{align} [3]
\end{enumerate}

\hfill \mbox{\textit{OCR FP1  Q7 [10]}}