OCR FP1 — Question 5 7 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeMethod of differences with given identity
DifficultyStandard +0.3 This is a standard telescoping series question with clear scaffolding. Part (i) is routine algebraic verification (2 marks). Part (ii) applies the given result to sum a series by telescoping—a technique explicitly taught in FP1. Part (iii) is immediate once part (ii) is complete. While it requires understanding of series and limits, the question structure guides students through each step, making it easier than average for an A-level question, though appropriately challenging for FP1 content.
Spec4.06b Method of differences: telescoping series

  1. Show that $$\frac{r+1}{r+2} - \frac{r}{r+1} = \frac{1}{(r+1)(r+2)}.$$ [2]
  2. Hence find an expression, in terms of \(n\), for $$\frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \ldots + \frac{1}{(n+1)(n+2)}.$$ [4]
  3. Hence write down the value of \(\sum_{r=1}^\infty \frac{1}{(r+1)(r+2)}\). [1]

\begin{enumerate}[label=(\roman*)]
\item Show that
$$\frac{r+1}{r+2} - \frac{r}{r+1} = \frac{1}{(r+1)(r+2)}.$$ [2]

\item Hence find an expression, in terms of $n$, for
$$\frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \ldots + \frac{1}{(n+1)(n+2)}.$$ [4]

\item Hence write down the value of $\sum_{r=1}^\infty \frac{1}{(r+1)(r+2)}$. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR FP1  Q5 [7]}}