AQA M3 2016 June — Question 5 12 marks

Exam BoardAQA
ModuleM3 (Mechanics 3)
Year2016
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeProjectile on inclined plane
DifficultyChallenging +1.8 This is a challenging M3 projectile motion problem requiring coordinate transformation to an inclined plane, finding impact time by solving simultaneous equations involving perpendicular distance, resolving velocities in non-standard directions, and analyzing rebound conditions with coefficient of restitution. The multi-step nature, geometric complexity, and requirement to derive an inequality for the rebound condition place it well above average difficulty, though it follows standard M3 techniques without requiring exceptional insight.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model6.03k Newton's experimental law: direct impact6.03l Newton's law: oblique impacts

A ball is projected from a point \(O\) above a smooth plane which is inclined at an angle of \(20°\) to the horizontal. The point \(O\) is at a perpendicular distance of \(1\) m from the inclined plane. The ball is projected with velocity \(22 \text{ m s}^{-1}\) at an angle of \(70°\) above the horizontal. The motion of the ball is in a vertical plane containing a line of greatest slope of the inclined plane. The ball strikes the inclined plane for the first time at a point \(A\). \includegraphics{figure_5}
    1. Find the time taken by the ball to travel from \(O\) to \(A\). [4 marks]
    2. Find the components of the velocity of the ball, parallel and perpendicular to the inclined plane, as it strikes the plane at \(A\). [4 marks]
  1. After striking \(A\), the ball rebounds and strikes the plane for a second time at a point further up than \(A\). The coefficient of restitution between the ball and the inclined plane is \(e\). Show that \(e < k\), where \(k\) is a constant to be determined. [4 marks]

(a)(i)
AnswerMarks Guidance
\(l = 22\sin 50° \cdot t - \frac{1}{2}g\cos 20° \cdot t^2\)M1 A1 M1: Perpendicular eqn with correct terms. A1: Correct equation
\(\frac{1}{2}g\cos 20° \cdot t^2 - 22\sin 50° \cdot t - l = 0\)dM1 dM1: Solution of their 3-term quadratic eqn.
\(t = 3.7185\ldots\) or \(3.719\)A1 A1: CAO, AWRT 3.72
(ii)
AnswerMarks Guidance
\(\dot{x} = 22\cos 50° - 9.8\sin 20° \cdot (3.7185\ldots)\)M1 M1: Parallel component of vel. with their time
\(\dot{x} = 1.678 \text{ ms}^{-1}\)A1 A1: Correct component, accept AWRT 1.68
\(\dot{y} = 22\sin 50° - 9.8\cos 20° \cdot (3.7185\ldots)\)M1 M1: Perpendicular component of vel. with their time
\(\dot{y} = 17.39 \text{ ms}^{-1}\)A1 A1: Correct component, accept AWRT -17.4
(b)
AnswerMarks Guidance
\(\gamma < 90° - 20°\)B1 B1: Seeing 90-20 or 70
\(\frac{17.39c}{1.678} < \tan(90° - 20°)\)B1F M1 B1F: Multiplying their vertical component by \(c\). M1: Correct inequality
\(e < 0.265\)A1 A1: CAO, accept AWRT 0.265
Total: 12 marks
**(a)(i)**

| $l = 22\sin 50° \cdot t - \frac{1}{2}g\cos 20° \cdot t^2$ | M1 A1 | M1: Perpendicular eqn with correct terms. A1: Correct equation |
| $\frac{1}{2}g\cos 20° \cdot t^2 - 22\sin 50° \cdot t - l = 0$ | dM1 | dM1: Solution of their 3-term quadratic eqn. |
| $t = 3.7185\ldots$ or $3.719$ | A1 | A1: CAO, AWRT 3.72 |

**(ii)**

| $\dot{x} = 22\cos 50° - 9.8\sin 20° \cdot (3.7185\ldots)$ | M1 | M1: Parallel component of vel. with their time |
| $\dot{x} = 1.678 \text{ ms}^{-1}$ | A1 | A1: Correct component, accept AWRT 1.68 |
| $\dot{y} = 22\sin 50° - 9.8\cos 20° \cdot (3.7185\ldots)$ | M1 | M1: Perpendicular component of vel. with their time |
| $\dot{y} = 17.39 \text{ ms}^{-1}$ | A1 | A1: Correct component, accept AWRT -17.4 |

**(b)**

| $\gamma < 90° - 20°$ | B1 | B1: Seeing 90-20 or 70 |
| $\frac{17.39c}{1.678} < \tan(90° - 20°)$ | B1F M1 | B1F: Multiplying their vertical component by $c$. M1: Correct inequality |
| $e < 0.265$ | A1 | A1: CAO, accept AWRT 0.265 |

**Total: 12 marks**

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A ball is projected from a point $O$ above a smooth plane which is inclined at an angle of $20°$ to the horizontal. The point $O$ is at a perpendicular distance of $1$ m from the inclined plane. The ball is projected with velocity $22 \text{ m s}^{-1}$ at an angle of $70°$ above the horizontal. The motion of the ball is in a vertical plane containing a line of greatest slope of the inclined plane. The ball strikes the inclined plane for the first time at a point $A$.

\includegraphics{figure_5}

\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Find the time taken by the ball to travel from $O$ to $A$. [4 marks]

\item Find the components of the velocity of the ball, parallel and perpendicular to the inclined plane, as it strikes the plane at $A$. [4 marks]
\end{enumerate}

\item After striking $A$, the ball rebounds and strikes the plane for a second time at a point further up than $A$.

The coefficient of restitution between the ball and the inclined plane is $e$.

Show that $e < k$, where $k$ is a constant to be determined. [4 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA M3 2016 Q5 [12]}}