AQA M3 2016 June — Question 4 14 marks

Exam BoardAQA
ModuleM3 (Mechanics 3)
Year2016
SessionJune
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImpulse and momentum (advanced)
TypeDirect collision of particles
DifficultyStandard +0.3 This is a standard M3 collision mechanics problem requiring conservation of momentum and Newton's restitution law. Part (a) involves routine application of two equations with two unknowns. Parts (b) and (c) require interpreting physical conditions (direction reversal, second collision occurs) as inequalities, which is typical M3 fare. Part (d) is straightforward impulse calculation. While multi-step, all techniques are standard textbook exercises with no novel insight required, making it slightly easier than average.
Spec6.03b Conservation of momentum: 1D two particles6.03c Momentum in 2D: vector form6.03f Impulse-momentum: relation6.03k Newton's experimental law: direct impact6.03l Newton's law: oblique impacts

A smooth uniform sphere \(A\), of mass \(m\), is moving with velocity \(8u\) in a straight line on a smooth horizontal table. A smooth uniform sphere \(B\), of mass \(4m\), has the same radius as \(A\) and is moving on the table with velocity \(u\). \includegraphics{figure_4} The sphere \(A\) collides directly with the sphere \(B\). The coefficient of restitution between \(A\) and \(B\) is \(e\).
    1. Find, in terms of \(u\) and \(e\), the velocities of \(A\) and \(B\) immediately after the collision. [6 marks]
    2. The direction of motion of \(A\) is reversed by the collision. Show that \(e > a\), where \(a\) is a constant to be determined. [2 marks]
  1. Subsequently, \(B\) collides with a fixed smooth vertical wall which is at right angles to the direction of motion of \(A\) and \(B\). The coefficient of restitution between \(B\) and the wall is \(\frac{2}{5}\). The sphere \(B\) collides with \(A\) again after rebounding from the wall. Show that \(e < b\), where \(b\) is a constant to be determined. [3 marks]
  2. Given that \(e = \frac{4}{7}\), find, in terms of \(m\) and \(u\), the magnitude of the impulse exerted on \(B\) by the wall. [3 marks]

(a)(i)
AnswerMarks Guidance
\(8mu + 4mu = mv_A + 4mv_B\) OEM1 A1 M1: Four non-zero momentum terms, A1: Correct eqn.
\(7eu = v_B - v_A\) OEM1 A1 M1: Eqn using \(e\). Allow sign errors. A1: Correct eqn.
\(v_B = \frac{u}{5}(12 + 7e)\) OEA1 A1: Correct vel of \(B\)
\(v_A = \frac{4u}{3}(3 - 7e)\) OEA1 A1: Correct vel of \(A\)
(ii)
AnswerMarks Guidance
\(\frac{4u}{5}(3 - 7e) < 0\)M1 M1: Their vel of \(A < 0\)
\(e > \frac{3}{7}\)A1 A1: CAO, accept AWRT 0.429
(b)
AnswerMarks Guidance
\(\frac{u}{5}(12 + 7e) \times \frac{2}{3} > \frac{4u}{5}(3 - 7e)\)B1 M1 B1: Correct rebound speed of \(B\). M1: Correct inequality
\(e < \frac{6}{7}\)A1 A1: CAO, AWRT 0.857
(c)
AnswerMarks Guidance
\(4m \times \frac{u}{5}\left(12 + 7 \times \frac{4}{7}\right) + 4m \times \frac{u}{5}\left(12 + 7 \times \frac{4}{7}\right) \times \frac{2}{3} =\)M1 A1 M1: Two correct momentum terms, allow sign errors. A1: Correct expression for impulse
\(\frac{64}{3}mu\) or \(21.3mu\)A1 A1: CAO (Must be positive)
Total: 14 marks
**(a)(i)**

| $8mu + 4mu = mv_A + 4mv_B$ OE | M1 A1 | M1: Four non-zero momentum terms, A1: Correct eqn. |
| $7eu = v_B - v_A$ OE | M1 A1 | M1: Eqn using $e$. Allow sign errors. A1: Correct eqn. |
| $v_B = \frac{u}{5}(12 + 7e)$ OE | A1 | A1: Correct vel of $B$ |
| $v_A = \frac{4u}{3}(3 - 7e)$ OE | A1 | A1: Correct vel of $A$ |

**(ii)**

| $\frac{4u}{5}(3 - 7e) < 0$ | M1 | M1: Their vel of $A < 0$ |
| $e > \frac{3}{7}$ | A1 | A1: CAO, accept AWRT 0.429 |

**(b)**

| $\frac{u}{5}(12 + 7e) \times \frac{2}{3} > \frac{4u}{5}(3 - 7e)$ | B1 M1 | B1: Correct rebound speed of $B$. M1: Correct inequality |
| $e < \frac{6}{7}$ | A1 | A1: CAO, AWRT 0.857 |

**(c)**

| $4m \times \frac{u}{5}\left(12 + 7 \times \frac{4}{7}\right) + 4m \times \frac{u}{5}\left(12 + 7 \times \frac{4}{7}\right) \times \frac{2}{3} =$ | M1 A1 | M1: Two correct momentum terms, allow sign errors. A1: Correct expression for impulse |
| $\frac{64}{3}mu$ or $21.3mu$ | A1 | A1: CAO (Must be positive) |

**Total: 14 marks**

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A smooth uniform sphere $A$, of mass $m$, is moving with velocity $8u$ in a straight line on a smooth horizontal table. A smooth uniform sphere $B$, of mass $4m$, has the same radius as $A$ and is moving on the table with velocity $u$.

\includegraphics{figure_4}

The sphere $A$ collides directly with the sphere $B$.

The coefficient of restitution between $A$ and $B$ is $e$.

\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Find, in terms of $u$ and $e$, the velocities of $A$ and $B$ immediately after the collision. [6 marks]

\item The direction of motion of $A$ is reversed by the collision. Show that $e > a$, where $a$ is a constant to be determined. [2 marks]
\end{enumerate}

\item Subsequently, $B$ collides with a fixed smooth vertical wall which is at right angles to the direction of motion of $A$ and $B$. The coefficient of restitution between $B$ and the wall is $\frac{2}{5}$.

The sphere $B$ collides with $A$ again after rebounding from the wall.

Show that $e < b$, where $b$ is a constant to be determined. [3 marks]

\item Given that $e = \frac{4}{7}$, find, in terms of $m$ and $u$, the magnitude of the impulse exerted on $B$ by the wall. [3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA M3 2016 Q4 [14]}}