Edexcel M2 — Question 1 5 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks5
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TopicMomentum and Collisions 1
TypeParticle-wall perpendicular collision
DifficultyModerate -0.8 This is a straightforward application of the coefficient of restitution formula to find the rebound speed, followed by a direct calculation of kinetic energy before and after impact. It requires only standard recall of formulas (e = v_separation/v_approach and KE = ½mv²) with simple arithmetic, making it easier than average but not trivial due to the multi-step calculation.
Spec6.02e Calculate KE and PE: using formulae6.03i Coefficient of restitution: e6.03k Newton's experimental law: direct impact
A heavy ball, of mass 2 kg, rolls along a horizontal surface. It strikes a vertical wall at a speed of 4 ms\(^{-1}\) and rebounds. The coefficient of restitution between the ball and the wall is 0.4. Find the kinetic energy lost in the impact. [5 marks]
AnswerMarks Guidance
Rebound speed = \(0.4(4) = 1.6 \text{ ms}^{-1}\)M1 A1
K.E. lost = \(\frac{1}{2} \times 2 \times (4^2 - 1.6^2) = 13.4 \text{ J}\)M1 A1 A1 5 marks 
Rebound speed = $0.4(4) = 1.6 \text{ ms}^{-1}$ | M1 A1 |
K.E. lost = $\frac{1}{2} \times 2 \times (4^2 - 1.6^2) = 13.4 \text{ J}$ | M1 A1 A1 | 5 marks
A heavy ball, of mass 2 kg, rolls along a horizontal surface. It strikes a vertical wall at a speed of 4 ms$^{-1}$ and rebounds. The coefficient of restitution between the ball and the wall is 0.4.

Find the kinetic energy lost in the impact. [5 marks]

\hfill \mbox{\textit{Edexcel M2  Q1 [5]}}
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