| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Newton's second law with vector forces (find acceleration or force) |
| Difficulty | Moderate -0.8 This is a straightforward M1 kinematics question using vector notation with constant acceleration. It requires direct application of standard SUVAT equations (v = u + at for part i, s = ut + ½at² for part ii, F = ma for part iii) with no problem-solving insight needed. The vector arithmetic is elementary, making this easier than average for A-level. |
| Spec | 1.10a Vectors in 2D: i,j notation and column vectors3.03d Newton's second law: 2D vectors |
A particle of mass 5 kg has constant acceleration. Initially, the particle is at $\begin{pmatrix} -1 \\ 2 \end{pmatrix}$ m with velocity $\begin{pmatrix} 2 \\ -3 \end{pmatrix}$ ms$^{-1}$; after 4 seconds the particle has velocity $\begin{pmatrix} 12 \\ 9 \end{pmatrix}$ ms$^{-1}$.
\begin{enumerate}[label=(\roman*)]
\item Calculate the acceleration of the particle. [2]
\item Calculate the position of the particle at the end of the 4 seconds. [3]
\item Calculate the force acting on the particle. [2]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI M1 Q5 [7]}}