OCR M1 2009 June — Question 4 9 marks

Exam BoardOCR
ModuleM1 (Mechanics 1)
Year2009
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeBasic trajectory calculations
DifficultyModerate -0.8 This is a straightforward three-part kinematics question using standard SUVAT equations with constant acceleration. All parts require direct application of memorized formulas (v² = u² + 2as for parts i and ii, v = u + at for part iii) with no problem-solving insight or multi-step reasoning. The calculations are simple and the question type is a textbook exercise that students practice repeatedly.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

An object is projected vertically upwards with speed \(7\) m s\(^{-1}\). Calculate
  1. the speed of the object when it is \(2.1\) m above the point of projection, [3]
  2. the greatest height above the point of projection reached by the object, [3]
  3. the time after projection when the object is travelling downwards with speed \(5.7\) m s\(^{-1}\). [3]

An object is projected vertically upwards with speed $7$ m s$^{-1}$. Calculate

\begin{enumerate}[label=(\roman*)]
\item the speed of the object when it is $2.1$ m above the point of projection, [3]
\item the greatest height above the point of projection reached by the object, [3]
\item the time after projection when the object is travelling downwards with speed $5.7$ m s$^{-1}$. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR M1 2009 Q4 [9]}}