| Exam Board | OCR |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2009 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Forces, equilibrium and resultants |
| Type | Resultant of coplanar forces |
| Difficulty | Moderate -0.8 This is a straightforward application of Pythagoras' theorem and basic trigonometry to perpendicular forces. Part (i) requires solving x²+(3x)²=36 for x, and part (ii) uses tan θ = 3x/x. Both are routine calculations with no problem-solving insight needed, making this easier than average but not trivial since it requires correct setup and execution. |
| Spec | 3.03e Resolve forces: two dimensions3.03p Resultant forces: using vectors |
\includegraphics{figure_1}
Two perpendicular forces have magnitudes $x$ N and $3x$ N (see diagram). Their resultant has magnitude $6$ N.
\begin{enumerate}[label=(\roman*)]
\item Calculate $x$. [3]
\item Find the angle the resultant makes with the smaller force. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR M1 2009 Q1 [6]}}