| Exam Board | OCR |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2009 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Velocity-time graph sketching |
| Difficulty | Moderate -0.8 This is a straightforward kinematics problem using constant acceleration equations and velocity-time graphs. All three parts follow standard M1 procedures: sketching a triangular v-t graph, using area under graph equals distance (½×3×v=6), then applying v=u+at with given acceleration to find deceleration. Requires only routine application of basic SUVAT concepts with no problem-solving insight needed. |
| Spec | 3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area3.02d Constant acceleration: SUVAT formulae |
The driver of a car accelerating uniformly from rest sees an obstruction. She brakes immediately bringing the car to rest with constant deceleration at a distance of $6$ m from its starting point. The car travels in a straight line and is in motion for $3$ seconds.
\begin{enumerate}[label=(\roman*)]
\item Sketch the $(t, v)$ graph for the car's motion. [2]
\item Calculate the maximum speed of the car during its motion. [3]
\item Hence, given that the acceleration of the car is $2.4$ m s$^{-2}$, calculate its deceleration. [4]
\end{enumerate}
\hfill \mbox{\textit{OCR M1 2009 Q2 [9]}}