OCR MEI C4 2013 June — Question 3 7 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Year2013
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeFind exact trigonometric values
DifficultyModerate -0.8 This question requires only standard recall of special angle triangles (45-45-90 and 30-60-90) and straightforward application of the tan addition formula tan(45°+30°). The geometric setup is well-known, and the algebraic manipulation is routine. While it has multiple parts worth 7 marks, each step follows a predictable pattern with no problem-solving insight required, making it easier than average.
Spec1.05g Exact trigonometric values: for standard angles1.05l Double angle formulae: and compound angle formulae

Using appropriate right-angled triangles, show that \(\tan 45° = 1\) and \(\tan 30° = \frac{1}{\sqrt{3}}\). Hence show that \(\tan 75° = 2 + \sqrt{3}\). [7]

Question 3:
AnswerMarks
310°
north:
north:
south:
15°
south:
Question 3:
3 | 10°
north:
1°
north:
5°
south:
15°
south:
Using appropriate right-angled triangles, show that $\tan 45° = 1$ and $\tan 30° = \frac{1}{\sqrt{3}}$.

Hence show that $\tan 75° = 2 + \sqrt{3}$. [7]

\hfill \mbox{\textit{OCR MEI C4 2013 Q3 [7]}}