Question 5:
5
8 Fig. 8 shows part of the curve y (cid:1) f(x), where
f(x) (cid:1) (ex (cid:3) 1)2 for x (cid:4) 0.
y
O x
Fig. 8
(i) Find f(cid:5)(x), and hence calculate the gradient of the curve y (cid:1) f(x) at the origin and at the point
(ln 2, 1). [5]
The function g(x) is defined by g(x)=ln ( 1+ x ) for x (cid:4) 0.
(ii) Show that f(x) and g(x) are inverse functions. Hence sketch the graph of y (cid:1) g(x).
Write down the gradient of the curvey (cid:1) g(x) at the point (1, ln 2). [5]
(iii) Show that Û Ù ( e x -1 )2 dx = 1e 2x -2e x +x+c.
ı 2
ln2
Hence evaluate Û Ù ( e x -1 )2 dx, giving your answer in an exact form. [5]
ı
0
(iv) Using your answer to part (iii), calculate the area of the region enclosed by the curve
y (cid:1) g(x), the x-axis and the line x (cid:1) 1. [3]
PMT
4753/01
ADVANCED GCE UNIT
MATHEMATICS (MEI)
Methods for Advanced Mathematics (C3)
MONDAY 11 JUNE 2007 Afternoon
Time: 1 hour 30 minutes
Additional materials:
Answer booklet (8 pages)
Graph paper
MEI Examination Formulae and Tables (MF2)
INSTRUCTIONS TO CANDIDATES
• Write your name, centre number and candidate number in the spaces provided on the answer booklet.
• Answer all the questions.
• You are permitted to use a graphical calculator in this paper.
• Final answers should be given to a degree of accuracy appropriate to the context.
INFORMATION FOR CANDIDATES
• The number of marks is given in brackets [ ] at the end of each question or part question.
• The total number of marks for this paper is 72.
ADVICE TO CANDIDATES
• Read each question carefully and make sure you know what you have to do before starting your
answer.
• You are advised that an answer may receive no marks unless you show sufficient detail of the
working to indicate that a correct method is being used.
This document consists of 4 printed pages.
HN/5 © OCR 2007 [K/100/3632] OCR is an exempt Charity [Turn over