Moderate -0.3 This is a straightforward differentiation and normal line question requiring standard techniques: find dy/dx, evaluate at the given point, find the normal gradient (negative reciprocal), then use point-slope form. It's slightly easier than average because it involves routine calculus procedures with no conceptual challenges, though the arithmetic with fractions requires some care.
Question 2:
2 | dy
[ = ] 32x3 c.a.o.
dx
dy
substitution of x = ½ in their
dx
−1
grad normal =
their4
when x = ½, y = 4 ½ o.e.
y−41 =−1(x−1)i.s.w
2 4 2 | M1
M1
M1
B1
A1 | [= 4]
y =−1 x+45 o.e.
4 8 | must see kx3
their 4 must be obtained by calculus