OCR MEI C2 2013 June — Question 5 5 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2013
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeFind derivative of simple polynomial (integer powers)
DifficultyModerate -0.8 This is a straightforward numerical differentiation question requiring only basic skills: drawing a tangent by eye, calculating gradient from a line, and computing a chord gradient using two points. All calculations involve simple exponential evaluation (2^x) and gradient formula. No conceptual depth or problem-solving required—purely mechanical application of standard techniques taught early in C2.
Spec1.06a Exponential function: a^x and e^x graphs and properties1.07a Derivative as gradient: of tangent to curve

\includegraphics{figure_5} Fig. 5 shows the graph of \(y = 2^x\).
  1. On the copy of Fig. 5, draw by eye a tangent to the curve at the point where \(x = 2\). Hence find an estimate of the gradient of \(y = 2^x\) when \(x = 2\). [3]
  2. Calculate the \(y\)-values on the curve when \(x = 1.8\) and \(x = 2.2\). Hence calculate another approximation to the gradient of \(y = 2^x\) when \(x = 2\). [2]

Part (i)
AnswerMarks Guidance
ruled line touching curve at \(x = 2\); their \(\frac{y_2 - y_1}{x_2 - x_1}\) from their tangent; answer in range 2.5 to 3.0 inclusiveM1, M1, A1 intent to touch, but must not clearly cut curve; may be on graph or in working; must use correct points from their line; their tangent may be at another point; both M1s must be awarded; M0 for reciprocal; (value is approx 2.773)
Part (ii)
AnswerMarks Guidance
3.482202253... and 4.59479342... rot to 3 or more sf; 2.78 to 2.7815 or 2.8B1, B1 mark the final answer; 2.781477917...
### Part (i)
ruled line touching curve at $x = 2$; their $\frac{y_2 - y_1}{x_2 - x_1}$ from their tangent; answer in range 2.5 to 3.0 inclusive | M1, M1, A1 | intent to touch, but must not clearly cut curve; may be on graph or in working; must use correct points from their line; their tangent may be at another point; both M1s must be awarded; M0 for reciprocal; (value is approx 2.773)

### Part (ii)
3.482202253... and 4.59479342... rot to 3 or more sf; 2.78 to 2.7815 or 2.8 | B1, B1 | mark the final answer; 2.781477917...
\includegraphics{figure_5}

Fig. 5 shows the graph of $y = 2^x$.
\begin{enumerate}[label=(\roman*)]
\item On the copy of Fig. 5, draw by eye a tangent to the curve at the point where $x = 2$. Hence find an estimate of the gradient of $y = 2^x$ when $x = 2$. [3]
\item Calculate the $y$-values on the curve when $x = 1.8$ and $x = 2.2$. Hence calculate another approximation to the gradient of $y = 2^x$ when $x = 2$. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C2 2013 Q5 [5]}}