| Exam Board | OCR MEI |
|---|---|
| Module | C2 (Core Mathematics 2) |
| Year | 2010 |
| Session | January |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Sine and Cosine Rules |
| Type | Point on side of triangle |
| Difficulty | Moderate -0.8 This is a straightforward two-part trigonometry question requiring standard application of the sine rule in triangle ABD, then the cosine rule in triangle BCD. Both are routine calculations with no problem-solving insight needed, making it easier than average but not trivial due to the multi-step nature. |
| Spec | 1.05b Sine and cosine rules: including ambiguous case |
\includegraphics{figure_7}
Fig. 7 shows triangle ABC, with AB = 8.4 cm. D is a point on AC such that angle ADB = 79°, BD = 5.6 cm and CD = 7.8 cm.
Calculate
\begin{enumerate}[label=(\roman*)]
\item angle BAD, [2]
\item the length BC. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI C2 2010 Q7 [5]}}