OCR MEI C2 2010 January — Question 3 3 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2010
SessionJanuary
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeFind exact trig values from given ratio
DifficultyModerate -0.8 This is a straightforward trigonometric identity question requiring students to find cos θ using the Pythagorean identity (cos²θ = 1 - sin²θ = 7/9, so cos θ = √7/3), then calculate tan θ = sin θ/cos θ = √2/√7 = √14/7. It's simpler than average as it only requires one standard technique with no problem-solving or conceptual difficulty, though the exact value arithmetic requires care.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=1

You are given that \(\sin \theta = \frac{\sqrt{2}}{3}\) and that \(\theta\) is an acute angle. Find the exact value of \(\tan \theta\). [3]

You are given that $\sin \theta = \frac{\sqrt{2}}{3}$ and that $\theta$ is an acute angle. Find the exact value of $\tan \theta$. [3]

\hfill \mbox{\textit{OCR MEI C2 2010 Q3 [3]}}