OCR MEI C1 — Question 5 13 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeSketch quadratic curve
DifficultyModerate -0.8 This is a straightforward C1 completing-the-square question with standard follow-ups. Part (i) is routine algebraic manipulation, parts (ii)-(iii) are direct applications requiring axis intercepts and sketching, and part (iv) involves equating expressions and solving a linear equation. All techniques are standard textbook exercises with no problem-solving insight required, making this easier than average.
Spec1.02c Simultaneous equations: two variables by elimination and substitution1.02e Complete the square: quadratic polynomials and turning points1.02f Solve quadratic equations: including in a function of unknown1.02m Graphs of functions: difference between plotting and sketching

  1. Write \(x^2 - 7x + 6\) in the form \((x - a)^2 + b\). [3]
  2. State the coordinates of the minimum point on the graph of \(y = x^2 - 7x + 6\). [2]
  3. Find the coordinates of the points where the graph of \(y = x^2 - 7x + 6\) crosses the axes and sketch the graph. [5]
  4. Show that the graphs of \(y = x^2 - 7x + 6\) and \(y = x^2 - 3x + 4\) intersect only once. Find the \(x\)-coordinate of the point of intersection. [3]

Question 5:
AnswerMarks
5ii
iii
AnswerMarks
iv(x − 3.5)2 − 6.25
(3.5, −6.25) o.e. or ft from
their (i)
(0, 6) (1, 0) (6, 0)
curve of correct shape
fully correct intns and min in
4th quadrant
x2 − 7x + 6 = x2 − 3x + 4
2 = 4x
AnswerMarks
x = ½ or 0.5 or 2/4 cao33
1+1
3
G1
G1
M1
M1
AnswerMarks
A1B1for a = 7/2 o.e,
B2 for b = −25/4 o.e. or M1
for 6 − (7/2)2 or 6 − (their a)2
allow x = 3.5 and y = −6.25 or
ft; allow shown on graph
1 each [stated or numbers
shown on graph]
or 4x − 2 = 0 (simple linear
form; condone one error)
condone no comment re only
AnswerMarks
one intn3
2
5
3
Question 5:
5 | ii
iii
iv | (x − 3.5)2 − 6.25
(3.5, −6.25) o.e. or ft from
their (i)
(0, 6) (1, 0) (6, 0)
curve of correct shape
fully correct intns and min in
4th quadrant
x2 − 7x + 6 = x2 − 3x + 4
2 = 4x
x = ½ or 0.5 or 2/4 cao | 33
1+1
3
G1
G1
M1
M1
A1 | B1for a = 7/2 o.e,
B2 for b = −25/4 o.e. or M1
for 6 − (7/2)2 or 6 − (their a)2
allow x = 3.5 and y = −6.25 or
ft; allow shown on graph
1 each [stated or numbers
shown on graph]
or 4x − 2 = 0 (simple linear
form; condone one error)
condone no comment re only
one intn | 3
2
5
3
\begin{enumerate}[label=(\roman*)]
\item Write $x^2 - 7x + 6$ in the form $(x - a)^2 + b$. [3]

\item State the coordinates of the minimum point on the graph of $y = x^2 - 7x + 6$. [2]

\item Find the coordinates of the points where the graph of $y = x^2 - 7x + 6$ crosses the axes and sketch the graph. [5]

\item Show that the graphs of $y = x^2 - 7x + 6$ and $y = x^2 - 3x + 4$ intersect only once. Find the $x$-coordinate of the point of intersection. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C1  Q5 [13]}}