Moderate -0.8 This is a straightforward C1 question requiring difference of two squares factorization followed by simple algebraic manipulation. The 'hence' part is routine application of Pythagoras' theorem using the simplified expression. Both parts are standard textbook exercises with no problem-solving insight required.
Simplify \((m^2 + 1)^2 - (m^2 - 1)^2\), showing your method.
Hence, given the right-angled triangle in Fig. 10, express \(p\) in terms of \(m\), simplifying your answer. [4]
\includegraphics{figure_3}
Question 3:
3 | correct expansion of both brackets
seen (may be unsimplified), or
difference of squares used
4m2 correctly obtained
[p =] [±]2m cao | M2
A1
A1 | M1 for one bracket expanded correctly;
for M2, condone done together and lack
of brackets round second expression if
correct when we insert the pair of
brackets | 4
Simplify $(m^2 + 1)^2 - (m^2 - 1)^2$, showing your method.
Hence, given the right-angled triangle in Fig. 10, express $p$ in terms of $m$, simplifying your answer. [4]
\includegraphics{figure_3}
\hfill \mbox{\textit{OCR MEI C1 Q3 [4]}}