Easy -1.2 This is a straightforward application of the point-gradient form of a line (y - y₁ = m(x - x₁)) followed by finding intercepts by substituting x=0 and y=0. It requires only basic algebraic manipulation with no problem-solving insight, making it easier than average but not trivial since it has multiple parts.
Find the equation of the line with gradient \(-2\) which passes through the point \((3, 1)\). Give your answer in the form \(y = ax + b\).
Find also the points of intersection of this line with the axes. [3]
Question 6:
6 | y = 2x + 7 isw
(0, 7) and (3.5, 0) oe or ft their y = 2x + c | 2
1
[3] | M1 for y 1 = 2(x 3) or
1 = 2 × 3 + c oe | condone lack of brackets and eg y = 7,
x = 3.5 or ft isw but 0 for poor notation
such as (3.5, 7) and no better answers
seen
Find the equation of the line with gradient $-2$ which passes through the point $(3, 1)$. Give your answer in the form $y = ax + b$.
Find also the points of intersection of this line with the axes. [3]
\hfill \mbox{\textit{OCR MEI C1 Q6 [3]}}