Moderate -0.8 This is a straightforward application of perpendicular gradients (negative reciprocal gives m = -1/2) and point-slope form. It requires only basic recall of perpendicular line properties and substitution into y - y₁ = m(x - x₁), making it easier than average but not trivial since it involves two distinct steps.
Find the equation of the line which is perpendicular to the line \(y = 2x - 5\) and which passes through the point \((4, 1)\). Give your answer in the form \(y = ax + b\). [3]
Question 4:
4 | y = 0.5x + 3 oe www isw | 3
[3] | B2 for 2y = x + 6 oe
1
or M1 for gradient = oe seen or used
2
and M1 for y 1 = their m (x 4) | for 3 marks must be in form y = ax + b
or M1 for y = their mx + c and (4, 1)
substituted
Find the equation of the line which is perpendicular to the line $y = 2x - 5$ and which passes through the point $(4, 1)$. Give your answer in the form $y = ax + b$. [3]
\hfill \mbox{\textit{OCR MEI C1 Q4 [3]}}