OCR MEI C1 — Question 6 5 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeComplete square then find vertex/turning point
DifficultyModerate -0.8 This is a straightforward completing the square question with standard coefficient manipulation and direct reading of the minimum from completed square form. It requires routine algebraic technique with no problem-solving insight, making it easier than average but not trivial due to the non-unit leading coefficient requiring factorization.
Spec1.02e Complete the square: quadratic polynomials and turning points

Express \(3x^2 - 12x + 5\) in the form \(a(x - b)^2 - c\). Hence state the minimum value of \(y\) on the curve \(y = 3x^2 - 12x + 5\). [5]

Question 6:
AnswerMarks
63(x  2)2  7 isw or a = 3, b = 2 c = 7 www
7 or ft4
B1
AnswerMarks
[5]B1 each for a = 3, b = 2 oe
and B2 for c = 7 oe
7
or M1 for  or for 5  their a(their b)2
3
5
or for theirb2 soi
3
AnswerMarks
B0 for (2, 7)condone omission of square symbol;
ignore ‘= 0’
may be implied by their answer
may be obtained by starting again eg
with calculus
Question 6:
6 | 3(x  2)2  7 isw or a = 3, b = 2 c = 7 www
7 or ft | 4
B1
[5] | B1 each for a = 3, b = 2 oe
and B2 for c = 7 oe
7
or M1 for  or for 5  their a(their b)2
3
5
or for theirb2 soi
3
B0 for (2, 7) | condone omission of square symbol;
ignore ‘= 0’
may be implied by their answer
may be obtained by starting again eg
with calculus
Express $3x^2 - 12x + 5$ in the form $a(x - b)^2 - c$. Hence state the minimum value of $y$ on the curve $y = 3x^2 - 12x + 5$. [5]

\hfill \mbox{\textit{OCR MEI C1  Q6 [5]}}