Edexcel C1 — Question 7 10 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeTangent parallel to given line
DifficultyModerate -0.8 This is a straightforward C1 differentiation question requiring standard techniques: differentiate a simple rational function, find gradient at a point, verify tangent equation, and find another point with the same gradient. All steps are routine with no problem-solving insight needed, making it easier than average but not trivial due to the multi-part structure and 10 total marks.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations

A curve has the equation \(y = \frac{x}{2} + 3 - \frac{1}{x}\), \(x \neq 0\). The point \(A\) on the curve has \(x\)-coordinate 2.
  1. Find the gradient of the curve at \(A\). [4]
  2. Show that the tangent to the curve at \(A\) has equation $$3x - 4y + 8 = 0.$$ [3]
The tangent to the curve at the point \(B\) is parallel to the tangent at \(A\).
  1. Find the coordinates of \(B\). [3]

AnswerMarks Guidance
(a) \(\frac{dy}{dx} = \frac{1}{2} + x^{-2}\)M1 A1
\(\text{grad} = \frac{1}{2} + 2^{-3} = \frac{3}{4}\)M1 A1
(b) \(x = 2 \therefore y = \frac{7}{2}\)B1
\(y - \frac{7}{2} = \frac{3}{4}(x - 2)\)M1
\(4y - 14 = 3x - 6\)
\(3x - 4y + 8 = 0\)A1
(c) at \(B\), grad \(= \frac{3}{4}\)
\(\therefore \frac{1}{2} + x^{-2} = \frac{3}{4}\)M1
\(x^2 = 4, \quad x = 2\) (at A), \(-2\)A1
\(\therefore B(-2, \frac{2}{3})\)A1 (10)
**(a)** $\frac{dy}{dx} = \frac{1}{2} + x^{-2}$ | M1 A1 | 
$\text{grad} = \frac{1}{2} + 2^{-3} = \frac{3}{4}$ | M1 A1 | 

**(b)** $x = 2 \therefore y = \frac{7}{2}$ | B1 | 
$y - \frac{7}{2} = \frac{3}{4}(x - 2)$ | M1 | 
$4y - 14 = 3x - 6$ | 
$3x - 4y + 8 = 0$ | A1 | 

**(c)** at $B$, grad $= \frac{3}{4}$ | 
$\therefore \frac{1}{2} + x^{-2} = \frac{3}{4}$ | M1 | 
$x^2 = 4, \quad x = 2$ (at A), $-2$ | A1 | 
$\therefore B(-2, \frac{2}{3})$ | A1 | (10)
A curve has the equation $y = \frac{x}{2} + 3 - \frac{1}{x}$, $x \neq 0$.

The point $A$ on the curve has $x$-coordinate 2.
\begin{enumerate}[label=(\alph*)]
\item Find the gradient of the curve at $A$. [4]
\item Show that the tangent to the curve at $A$ has equation
$$3x - 4y + 8 = 0.$$ [3]
\end{enumerate}

The tangent to the curve at the point $B$ is parallel to the tangent at $A$.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find the coordinates of $B$. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q7 [10]}}