Edexcel C1 — Question 5 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeBasic power rule differentiation
DifficultyModerate -0.3 This is a straightforward differentiation question requiring simplification of a quotient, then applying the power rule (not actually the chain rule despite the topic label). Part (a) is routine algebra and differentiation; part (b) is a simple verification requiring one more differentiation. Slightly easier than average due to being purely procedural with no problem-solving element, but the algebraic manipulation and second derivative add minor complexity beyond the most basic questions.
Spec1.07d Second derivatives: d^2y/dx^2 notation1.07i Differentiate x^n: for rational n and sums

Given that $$y = \frac{x^4 - 3}{2x^2},$$
  1. find \(\frac{dy}{dx}\), [4]
  2. show that \(\frac{d^2y}{dx^2} = \frac{x^4 - 9}{x^4}\). [2]

AnswerMarks Guidance
(a) \(y = \frac{1}{2}x^2 - \frac{3}{4}x^{-2}\)M1 A1
\(\frac{dy}{dx} = x + 3x^{-3}\)M1 A1
(b) \(\frac{d^2y}{dx^2} = 1 - 9x^{-4} = \frac{x^4 - 9}{x^4}\)M1 A1 (6)
**(a)** $y = \frac{1}{2}x^2 - \frac{3}{4}x^{-2}$ | M1 A1 | 
$\frac{dy}{dx} = x + 3x^{-3}$ | M1 A1 | 

**(b)** $\frac{d^2y}{dx^2} = 1 - 9x^{-4} = \frac{x^4 - 9}{x^4}$ | M1 A1 | (6)
Given that
$$y = \frac{x^4 - 3}{2x^2},$$
\begin{enumerate}[label=(\alph*)]
\item find $\frac{dy}{dx}$, [4]
\item show that $\frac{d^2y}{dx^2} = \frac{x^4 - 9}{x^4}$. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q5 [6]}}