OCR MEI C1 2011 June — Question 1 3 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2011
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve linear inequality
DifficultyEasy -1.8 This is a straightforward linear inequality requiring only basic algebraic manipulation: expand brackets, collect like terms, and divide by a positive coefficient. It's a routine C1 exercise with no conceptual challenges, significantly easier than average A-level questions.
Spec1.02g Inequalities: linear and quadratic in single variable

Solve the inequality \(6(x + 3) > 2x + 5\). [3]

AnswerMarks Guidance
\(x > -13/4\) o.e. iswM1 For \(13 > -4x\) (may be followed by \(13/-4 > x\), which earns no further credit); \(6x + 3 > 2x + 5\) is an error not an MR; can get M1 for \(4x > ...\) following this, and then a possible B1
condone \(x > 13/-4\) or \(13/-4 < x\);M2 for \(4x > -13\) or M1 for one side of this correct with correct inequality, and B1 for final step ft from their \(ax > b\) or \(c > dx\) for \(a \neq 1\) and \(d \neq 1\) If no working shown, allow SC1 for \(-13/4\) o.e with equals sign or wrong inequality
$x > -13/4$ o.e. isw | M1 | For $13 > -4x$ (may be followed by $13/-4 > x$, which earns no further credit); $6x + 3 > 2x + 5$ is an error not an MR; can get M1 for $4x > ...$ following this, and then a possible B1

condone $x > 13/-4$ or $13/-4 < x$; | M2 for $4x > -13$ or M1 for one side of this correct with correct inequality, and B1 for final step ft from their $ax > b$ or $c > dx$ for $a \neq 1$ and $d \neq 1$ | If no working shown, allow SC1 for $-13/4$ o.e with equals sign or wrong inequality
Solve the inequality $6(x + 3) > 2x + 5$. [3]

\hfill \mbox{\textit{OCR MEI C1 2011 Q1 [3]}}