OCR MEI C1 2006 June — Question 9 5 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2006
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeEvaluate numerical powers
DifficultyEasy -1.3 This is a straightforward indices manipulation question requiring only direct application of basic index laws. Part (i) involves simplifying a fraction of fourth roots (routine calculation), and part (ii) requires expanding brackets and cancelling terms using standard index rules. Both parts are mechanical exercises with no problem-solving element, making this easier than average for A-level.
Spec1.02a Indices: laws of indices for rational exponents

Simplify the following.
  1. \(\frac{16^{\frac{1}{4}}}{81^{\frac{1}{4}}}\) [2]
  2. \(\frac{12(a^3b^2c)^4}{4a^2c^6}\) [3]

AnswerMarks Guidance
(i) \(\frac{4}{27}\)2 marks 1 for \(4\) or \(27\)
(ii) \(3a^{10}b^6c^2\) or \(\frac{3a^{10}b^6}{c^2}\)3 marks 2 for \(3\) 'elements' correct, 1 for 2 elements correct, \(-1\) for any adding of elements; mark final answer; condone correct but unnecessary brackets
5 marks
(i) $\frac{4}{27}$ | 2 marks | 1 for $4$ or $27$

(ii) $3a^{10}b^6c^2$ or $\frac{3a^{10}b^6}{c^2}$ | 3 marks | 2 for $3$ 'elements' correct, 1 for 2 elements correct, $-1$ for any adding of elements; mark final answer; condone correct but unnecessary brackets

| | 5 marks |
Simplify the following.

\begin{enumerate}[label=(\roman*)]
\item $\frac{16^{\frac{1}{4}}}{81^{\frac{1}{4}}}$ [2]

\item $\frac{12(a^3b^2c)^4}{4a^2c^6}$ [3]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C1 2006 Q9 [5]}}