OCR C1 2013 January — Question 8 7 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2013
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscriminant and conditions for roots
TypeFind range for no real roots
DifficultyStandard +0.3 This is a standard discriminant problem requiring students to set b²-4ac < 0 and solve the resulting quadratic inequality. While it involves multiple steps (forming the discriminant, simplifying, factorizing, and determining the inequality solution), these are all routine C1 techniques with no novel insight required, making it slightly above average difficulty.
Spec1.02d Quadratic functions: graphs and discriminant conditions

The quadratic equation \(kx^2 + (3k - 1)x - 4 = 0\) has no real roots. Find the set of possible values of \(k\). [7]

\((3k - 1)^2 - 4 \times k \times k - 4 = 9k^2 + 10k + 1\), \(9k^2 + 10k + 1 < 0\), \((9k + 1)(k + 1) < 0\), \(-1, -\frac{1}{9}\), \(-1 < k < -\frac{1}{9}\)
AnswerMarks Guidance
*M1Attempts \(b^2 - 4ac\) or an equation or inequality involving \(b^2\) and \(4ac\). Must involve \(k^2\) in first term (but no \(x\) anywhere). If \(b^2 - 4ac\) not stated, must be clear attempt. Must be working with the discriminant explicitly and not only as part of the quadratic formula. Allow \(\sqrt{b^2 - 4ac}\) for first M1 A1
A1Correct discriminant, simplified to 3 terms
M1States discriminant \(< 0\) or \(b^2 < 4ac\). Can be awarded at any stage. Doesn't need first M1. No square root here.
DM1Correct method to find roots of a three term quadratic
A1Both values of \(k\) correct
M1Chooses "inside region" of inequality Allow correct region for their inequality. Do not allow "\(k < -\frac{1}{9}\) or \(k > -1\)"; Do not allow "\(k < -\frac{1}{9}\) or \(k > -1\)".
A1Allow "\(k < -\frac{1}{9}\) and \(k > -1\)" etc. must be strict inequalities for A mark
[7]
$(3k - 1)^2 - 4 \times k \times k - 4 = 9k^2 + 10k + 1$, $9k^2 + 10k + 1 < 0$, $(9k + 1)(k + 1) < 0$, $-1, -\frac{1}{9}$, $-1 < k < -\frac{1}{9}$

| *M1 | Attempts $b^2 - 4ac$ or an equation or inequality involving $b^2$ and $4ac$. Must involve $k^2$ in first term (but no $x$ anywhere). If $b^2 - 4ac$ not stated, must be clear attempt. | Must be working with the discriminant explicitly and not only as part of the quadratic formula. Allow $\sqrt{b^2 - 4ac}$ for first M1 A1 |
| A1 | Correct discriminant, simplified to 3 terms | |
| M1 | States discriminant $< 0$ or $b^2 < 4ac$. | Can be awarded at any stage. Doesn't need first M1. No square root here. |
| DM1 | Correct method to find roots of a three term quadratic | |
| A1 | Both values of $k$ correct | |
| M1 | Chooses "inside region" of inequality | Allow correct region for their inequality. Do not allow "$k < -\frac{1}{9}$ or $k > -1$"; Do not allow "$k < -\frac{1}{9}$ or $k > -1$". |
| A1 | Allow "$k < -\frac{1}{9}$ and $k > -1$" etc. must be strict inequalities for A mark | |
| [7] | | |
The quadratic equation $kx^2 + (3k - 1)x - 4 = 0$ has no real roots. Find the set of possible values of $k$. [7]

\hfill \mbox{\textit{OCR C1 2013 Q8 [7]}}