OCR C1 2013 January — Question 1 5 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2013
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSolving quadratics and applications
TypeQuadratic with surd roots, exact form
DifficultyModerate -0.8 This is a straightforward two-part question testing basic quadratic formula application and simple differentiation. Part (i) requires routine use of the quadratic formula with minimal algebraic manipulation to simplify surds. Part (ii) is a standard differentiation exercise requiring only the power rule and substitution. Both parts are mechanical procedures with no problem-solving or conceptual challenge, making this easier than the average A-level question.
Spec1.02f Solve quadratic equations: including in a function of unknown1.07i Differentiate x^n: for rational n and sums

  1. Solve the equation \(x^2 - 6x - 2 = 0\), giving your answers in simplified surd form. [3]
  2. Find the gradient of the curve \(y = x^2 - 6x - 2\) at the point where \(x = -5\). [2]

(i)
\(6 \pm \sqrt{(-6)^2 - 4 \times 1 \times -2} / 2 \times 1 = 6 \pm \sqrt{44} / 2 = 3 \pm \sqrt{11}\)
OR: \((x-3)^2 - 9 - 2 = 0\), \(x - 3 = \pm\sqrt{11}\), \(x = 3 \pm \sqrt{11}\)
AnswerMarks Guidance
M1Valid attempt to use quadratic formula No marks for attempting to factorise
A1Both roots correct and simplified Must get to \((x-3)\) and \(\pm\) stage for the M mark, constants combined correctly gets A1
A1Rearranged to correct form (cao)
[3]
(ii)
\(\frac{dy}{dx} = 2x - 6 = -16\)
AnswerMarks
B1
B1www
[2]
### (i)
$6 \pm \sqrt{(-6)^2 - 4 \times 1 \times -2} / 2 \times 1 = 6 \pm \sqrt{44} / 2 = 3 \pm \sqrt{11}$

OR: $(x-3)^2 - 9 - 2 = 0$, $x - 3 = \pm\sqrt{11}$, $x = 3 \pm \sqrt{11}$

| M1 | Valid attempt to use quadratic formula | No marks for attempting to factorise |
| A1 | Both roots correct and simplified | Must get to $(x-3)$ and $\pm$ stage for the M mark, constants combined correctly gets A1 |
| A1 | Rearranged to correct form (cao) | |
| [3] | | |

### (ii)
$\frac{dy}{dx} = 2x - 6 = -16$

| B1 | | |
| B1 | www | |
| [2] | | |
\begin{enumerate}[label=(\roman*)]
\item Solve the equation $x^2 - 6x - 2 = 0$, giving your answers in simplified surd form. [3]
\item Find the gradient of the curve $y = x^2 - 6x - 2$ at the point where $x = -5$. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR C1 2013 Q1 [5]}}