Edexcel D1 2006 June — Question 7 14 marks

Exam BoardEdexcel
ModuleD1 (Decision Mathematics 1)
Year2006
SessionJune
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNetwork Flows
TypeCalculate cut capacity
DifficultyModerate -0.3 This is a standard D1 network flows question testing the max-flow min-cut algorithm with clear scaffolding. Parts (a)-(d) involve routine application of the labelling procedure following a given initial flow, requiring only careful bookkeeping. Part (e) asks for proof via max-flow min-cut theorem, which is a standard result. While multi-step with 14 marks total, it's methodical rather than conceptually challenging—slightly easier than average A-level maths due to the algorithmic nature and heavy guidance.
Spec7.04f Network problems: choosing appropriate algorithm

\includegraphics{figure_5} Figure 5 shows a capacitated, directed network. The capacity of each arc is shown on each arc. The numbers in circles represent an initial flow from S to T. Two cuts \(C_1\) and \(C_2\) are shown on Figure 5.
  1. Write down the capacity of each of the two cuts and the value of the initial flow. [3]
  2. Complete the initialisation of the labelling procedure on Diagram 1 by entering values along arcs AC, CD, DE and DT. [2]
  3. Hence use the labelling procedure to find a maximal flow through the network. You must list each flow-augmenting path you use, together with its flow. [5]
  4. Show your maximal flow pattern on Diagram 2. [2]
  5. Prove that your flow is maximal. [2]

AnswerMarks
(a) \(c_1 = 103\), \(c_2 = 177\), Slack = 76B1, B1, B1(3)
(b) [Network diagram with labels: A connected to nodes with various weights and degrees]m1 A1(2)
(c) e.g. \(SBCDT - 6\); \(SBCDET - 1\); \(SBACDET - 15\); max flow is 98m1 A3,2,1,0(5)
(d) [Network diagram showing flow values on edges with maximum flow = minimum cut interpretation]m1 A1(2)
(e) Maximum flow = minimum cut; cut through AD, AC, BC and BEm1 A1(2)
Summary of Mark Types Used
- m1: Method mark (one mark)
- m: Method
- A1: Accuracy mark (one mark)
- A: Answer/Accuracy
- B1, B2: Independent marks
- B2,1,0: Graduated mark scheme (2, 1, or 0)
- A1(L1): Accuracy mark on same line, level 1
- DM1: Dependent method mark
- cao: Correct answer only
- c.a.o: Correct answer only
(a) $c_1 = 103$, $c_2 = 177$, Slack = 76 | B1, B1, B1(3)

(b) [Network diagram with labels: A connected to nodes with various weights and degrees] | m1 A1(2)

(c) e.g. $SBCDT - 6$; $SBCDET - 1$; $SBACDET - 15$; max flow is 98 | m1 A3,2,1,0(5)

(d) [Network diagram showing flow values on edges with maximum flow = minimum cut interpretation] | m1 A1(2)

(e) Maximum flow = minimum cut; cut through AD, AC, BC and BE | m1 A1(2)

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## Summary of Mark Types Used

- **m1**: Method mark (one mark)
- **m**: Method
- **A1**: Accuracy mark (one mark)
- **A**: Answer/Accuracy
- **B1, B2**: Independent marks
- **B2,1,0**: Graduated mark scheme (2, 1, or 0)
- **A1(L1)**: Accuracy mark on same line, level 1
- **DM1**: Dependent method mark
- **cao**: Correct answer only
- **c.a.o**: Correct answer only
\includegraphics{figure_5}

Figure 5 shows a capacitated, directed network. The capacity of each arc is shown on each arc. The numbers in circles represent an initial flow from S to T.

Two cuts $C_1$ and $C_2$ are shown on Figure 5.

\begin{enumerate}[label=(\alph*)]
\item Write down the capacity of each of the two cuts and the value of the initial flow. [3]

\item Complete the initialisation of the labelling procedure on Diagram 1 by entering values along arcs AC, CD, DE and DT. [2]

\item Hence use the labelling procedure to find a maximal flow through the network. You must list each flow-augmenting path you use, together with its flow. [5]

\item Show your maximal flow pattern on Diagram 2. [2]

\item Prove that your flow is maximal. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel D1 2006 Q7 [14]}}