| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2013 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions |
| Type | Direct collision, find impulse magnitude |
| Difficulty | Moderate -0.8 This is a straightforward M1 momentum question requiring direct application of the impulse-momentum theorem to each particle separately. Students need to set up sign conventions and apply J = mv - mu twice, but no problem-solving insight is required—it's a standard textbook exercise with clearly given values and routine algebraic manipulation. |
| Spec | 6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation |
Two particles $A$ and $B$, of mass 2 kg and 3 kg respectively, are moving towards each other in opposite directions along the same straight line on a smooth horizontal surface. The particles collide directly. Immediately before the collision the speed of $A$ is 5 m s$^{-1}$ and the speed of $B$ is 6 m s$^{-1}$. The magnitude of the impulse exerted on $B$ by $A$ is 14 N s. Find
\begin{enumerate}[label=(\alph*)]
\item the speed of $A$ immediately after the collision, [3]
\item the speed of $B$ immediately after the collision. [3]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2013 Q1 [6]}}