| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2013 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Two particles: same start time, different heights |
| Difficulty | Moderate -0.3 This is a straightforward SUVAT problem requiring students to set up two equations for vertical motion and solve simultaneously. While it involves two objects and requires careful bookkeeping of initial conditions, the mathematical steps are routine (forming quadratic equations, solving for t, substituting back). The 7 marks reflect multiple steps rather than conceptual difficulty, making it slightly easier than average for M1. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form |
At time $t = 0$, two balls $A$ and $B$ are projected vertically upwards. The ball $A$ is projected vertically upwards with speed 2 m s$^{-1}$ from a point 50 m above the horizontal ground. The ball $B$ is projected vertically upwards from the ground with speed 20 m s$^{-1}$. At time $t = T$ seconds, the two balls are at the same vertical height, $h$ metres, above the ground. The balls are modelled as particles moving freely under gravity. Find
\begin{enumerate}[label=(\alph*)]
\item the value of $T$, [5]
\item the value of $h$. [2]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2013 Q4 [7]}}