| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2004 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions |
| Type | Given impulse, find velocity or mass |
| Difficulty | Moderate -0.8 This is a straightforward M1 mechanics question testing standard SUVAT equations and impulse-momentum theorem. Part (a) requires routine application of kinematic equations with given values, and part (b) is a direct application of the impulse formula. Both parts involve minimal problem-solving and are typical textbook exercises with clear solution paths. |
| Spec | 3.02d Constant acceleration: SUVAT formulae6.03f Impulse-momentum: relation |
| Answer | Marks |
|---|---|
| 2 | (a) ‘v = u + at’: 9.5 = 5 + 1.5a ⇒ a = 3 M1 A1 |
Question 2:
2 | (a) ‘v = u + at’: 9.5 = 5 + 1.5a ⇒ a = 3 M1 A1
↓
Hence v2 = 52 + 2 x 3 x 24 M1
= 169 ⇒ v = 13 m s–1 (*) A1
(4)
(b) ‘I = mv – mu’ : –30 = 2(v – 13) ⇒ v = (–) 2 m s–1 M1 A1
In direction of CA (o.e.) A1
(3)
(a) 2nd M1 for equation in v (and numbers) only
Final A1 is cso
(b) M1 for valid impulse = momentum change equn with 3 non-zero terms including ‘30’ and ‘13’
A1 for ‘30’ and ‘13’ with same sign
A1 for direction as ‘CB’ or anything convincing!
NB both A’s in (b) are cao = cso!A particle $P$ is moving with constant acceleration along a straight horizontal line $ABC$, where $AC = 24$ m. Initially $P$ is at $A$ and is moving with speed $5$ m s$^{-1}$ in the direction $AB$. After $1.5$ s, the direction of motion of $P$ is unchanged and $P$ is at $B$ with speed $9.5$ m s$^{-1}$.
\begin{enumerate}[label=(\alph*)]
\item Show that the speed of $P$ at $C$ is $13$ m s$^{-1}$. [4]
\end{enumerate}
The mass of $P$ is $2$ kg. When $P$ reaches $C$, an impulse of magnitude $30$ Ns is applied to $P$ in the direction $CB$.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the velocity of $P$ immediately after the impulse has been applied, stating clearly the direction of motion of $P$ at this instant. [3]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2004 Q2 [7]}}