Edexcel M1 2022 October — Question 1 5 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2022
SessionOctober
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCoalescence collision
DifficultyModerate -0.8 This is a straightforward application of conservation of momentum for perfectly inelastic collision followed by impulse calculation using change in momentum. Both parts require direct formula application with no problem-solving insight or geometric reasoning—easier than average A-level questions.
Spec6.03a Linear momentum: p = mv6.03b Conservation of momentum: 1D two particles6.03e Impulse: by a force6.03f Impulse-momentum: relation

A railway truck \(S\) of mass 20 tonnes is moving along a straight horizontal track when it collides with another railway truck \(T\) of mass 30 tonnes which is at rest. Immediately before the collision the speed of \(S\) is \(4\text{ ms}^{-1}\) As a result of the collision, the two railway trucks join together. Find
  1. the common speed of the railway trucks immediately after the collision, [2]
  2. the magnitude of the impulse exerted on \(S\) in the collision, stating the units of your answer. [3]

Question 1:

AnswerMarks
1(a)2 0 0 0 0  4 = 5 0 0 0 0 v
OR 2 0 ( − v − ( − 4 ) ) = 3 0 ( v − 0 )
AnswerMarks
v = 1 . 6 ( m − s 1 )M1
A1
(2)
AnswerMarks
1(a)M1 for a CLM equation, condone sign errors and extra g’s and any equivalent
equation (e.g. 2 x 4 = 5v, 20 x 4 = 50v, 200 x 4 = 500v,… etc)
OR : for equating impulses
A1 oe Units not needed but must be positive.

AnswerMarks Guidance
1(b)20000(1.6−4) OR  3 0 0 0 0  1 .6 M1A1ft
48000 N s or 48 kN sA1
.(3)
(5)
Notes for question 1
AnswerMarks
1(b)M1 impulse-momentum equation, dimensionally correct, correct no. of
terms, condone sign errors but must be attempting a difference of momenta
(allow 20 or 30 for the mass, M0 if g included or mass omitted)
A1ft a correct equation, follow through on their v
(allow 20 or 30 for the mass)
N.B. If using S to find the impulse, 4 and their v must have opposite signs
when awarding the A1ft.
A1 cao units needed (allow kg m s − 1 ) and must be positive.
Question 1:
--- 1(a) ---
1(a) | 2 0 0 0 0  4 = 5 0 0 0 0 v
OR 2 0 ( − v − ( − 4 ) ) = 3 0 ( v − 0 )
v = 1 . 6 ( m − s 1 ) | M1
A1
(2)
1(a) | M1 for a CLM equation, condone sign errors and extra g’s and any equivalent
equation (e.g. 2 x 4 = 5v, 20 x 4 = 50v, 200 x 4 = 500v,… etc)
OR : for equating impulses
A1 oe Units not needed but must be positive.
--- 1(b) ---
1(b) | 20000(1.6−4) OR  3 0 0 0 0  1 .6 | M1A1ft
48000 N s or 48 kN s | A1
. | (3)
(5)
Notes for question 1
1(b) | M1 impulse-momentum equation, dimensionally correct, correct no. of
terms, condone sign errors but must be attempting a difference of momenta
(allow 20 or 30 for the mass, M0 if g included or mass omitted)
A1ft a correct equation, follow through on their v
(allow 20 or 30 for the mass)
N.B. If using S to find the impulse, 4 and their v must have opposite signs
when awarding the A1ft.
A1 cao units needed (allow kg m s − 1 ) and must be positive.
A railway truck $S$ of mass 20 tonnes is moving along a straight horizontal track when it collides with another railway truck $T$ of mass 30 tonnes which is at rest. Immediately before the collision the speed of $S$ is $4\text{ ms}^{-1}$

As a result of the collision, the two railway trucks join together.

Find
\begin{enumerate}[label=(\alph*)]
\item the common speed of the railway trucks immediately after the collision, [2]

\item the magnitude of the impulse exerted on $S$ in the collision, stating the units of your answer. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2022 Q1 [5]}}