Edexcel FP2 2008 June — Question 11

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2008
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex numbers 2
TypeExpress roots in trigonometric form
DifficultyChallenging +1.2 This is a standard Further Maths FP2 question testing well-rehearsed techniques: proof by induction (routine for this theorem), binomial expansion to derive multiple angle formulas, and algebraic manipulation using special angle properties. While it requires multiple steps and FP2 content is inherently harder than single maths, these are textbook exercises without novel insight required.
Spec4.01a Mathematical induction: construct proofs4.02q De Moivre's theorem: multiple angle formulae

De Moivre's theorem states that \((\cos\theta + i\sin\theta)^n = \cos n\theta + i\sin n\theta\) for \(n \in \mathbb{R}\)
  1. Use induction to prove de Moivre's theorem for \(n \in \mathbb{Z}^+\). (5)
  2. Show that \(\cos 5\theta = 16\cos^5\theta - 20\cos^3\theta + 5\cos\theta\) (5)
  3. Hence show that \(2\cos\frac{\pi}{10}\) is a root of the equation $$x^4 - 5x^2 + 5 = 0$$ (3)

De Moivre's theorem states that $(\cos\theta + i\sin\theta)^n = \cos n\theta + i\sin n\theta$ for $n \in \mathbb{R}$

\begin{enumerate}[label=(\alph*)]
\item Use induction to prove de Moivre's theorem for $n \in \mathbb{Z}^+$. (5)

\item Show that $\cos 5\theta = 16\cos^5\theta - 20\cos^3\theta + 5\cos\theta$ (5)

\item Hence show that $2\cos\frac{\pi}{10}$ is a root of the equation
$$x^4 - 5x^2 + 5 = 0$$ (3)
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP2 2008 Q11}}